题解 | #统计字符#

有点懒，直接用string模块的字符集去处理判断拉倒，无脑干

from string import ascii_letters, digits, punctuation, whitespace

while True:
    try:
        l_count, d_count, p_count, w_count = 0, 0, 0, 0
        for x in input():
            if x in ascii_letters:
                l_count += 1
            elif x in digits:
                d_count += 1
            elif x in punctuation:
                p_count += 1
            elif x in whitespace:
                w_count += 1
        print(l_count)
        print(w_count)
        print(d_count)
        print(p_count)
    except EOFError:
        break