题解 | #反转链表#
反转链表
http://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/*
struct ListNode {
int val;
struct ListNode *next;
ListNode(int x) :
val(x), next(NULL) {
}
};*/
class Solution {
public:
ListNode* ReverseList(ListNode* pHead) {
ListNode* pNewHead=nullptr;
while(pHead)
{
ListNode* temp=pHead->next;
pHead->next=pNewHead;
pNewHead=pHead;
pHead=temp;
}
return pNewHead;
}
};