题解 | #字符串加密#

//先去重获得秘钥然后进行二次去重获取字典，使用asc码差值获取字母位置
while(key = readline()) {
    const newStr =  Array.from(new Set(key.split(''))).join('').toLowerCase();
    const book = newStr + 'abcdefghijklmnopqrstuvwxyz';
    const bookList = Array.from(new Set(book.split('')));
    
    const passStr = readline().split('');
    let result = [];
    for (let char of passStr) {
        let code = char.charCodeAt();
        if (code >=65 && code <= 90) {
            let index = code - 65;
            let str = bookList[index].toUpperCase();
            result.push(str);
        } else if (code >=97 && code <= 122) {
            let index = code - 97;
            result.push(bookList[index]);
        } else {
            let str = String.fromCharCode(code);
            result.push(str);
        }
    }
    print(result.join(''));
}