题解 | #获得积分最多的人(一)#
获得积分最多的人(一)
http://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
select u.name,t.grade_num
from user u
join (select user_id,sum(grade_num) grade_num from grade_info group by user_id ) t
on u.id = t.user_id
order by t.grade_num desc
limit 1;
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