题解 | #二叉树的镜像#
二叉树的镜像
http://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param pRoot TreeNode类
# @return TreeNode类
#
class Solution:
def Mirror(self , pRoot ):
# write code here
if pRoot is None:
return pRoot
pRoot.left, pRoot.right = pRoot.right, pRoot.left
self.Mirror(pRoot.left)
self.Mirror(pRoot.right)
return pRoot