题解 | #时间转换#

#include<stdio.h>
int main(){
    int m;
    scanf("%d",&m);
    int h,x,t;
    h=m/3600;
    x=(m-3600*h)/60;
    t= m-3600*h-60*x;
    printf("%d %d %d",h,x,t);
    return 0;
}