题解 | #字符逆序#
字符逆序
http://www.nowcoder.com/practice/cc57022cb4194697ac30bcb566aeb47b
while True: try: string1=list(map(str,input())) string1.reverse() s=''.join(string1) print(s) except: break
字符逆序
http://www.nowcoder.com/practice/cc57022cb4194697ac30bcb566aeb47b
while True: try: string1=list(map(str,input())) string1.reverse() s=''.join(string1) print(s) except: break
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