题解 | #判断二叉树是否对称#
判断二叉树是否对称
http://www.nowcoder.com/practice/1b0b7f371eae4204bc4a7570c84c2de1
package org.example.test; import java.util.LinkedList; import java.util.Queue; import java.util.Stack; public class SymmetricTest { public static void main(String[] args) { TreeNode node1 = new TreeNode(1); TreeNode node2 = new TreeNode(2); TreeNode node3 = new TreeNode(2); node1.left = node2; node1.right = node3; System.out.println(isSymmetric(node1)); } static public class TreeNode { int val; TreeNode left; TreeNode right; public TreeNode(int val) { this.val = val; } } /** * 迭代算法,BFS * * @param root * @return */ public static boolean isSymmetric(TreeNode root) { // write code here if (root == null) { return true; } Queue<TreeNode> queue = new LinkedList<>(); queue.offer(root); Stack<Integer> stack = new Stack<>(); while (!queue.isEmpty()) { int size = queue.size(); if (size % 2 != 0 && queue.peek() != root) { return false; } int half = size / 2; while (size > 0) { TreeNode node = queue.poll(); if (size > half) { stack.push(node == null ? 1 : node.val); } else { int tmp = node == null ? 1 : node.val; if (stack.pop() != tmp) { return false; } } size--; if (node == null) { continue; } if (node.left != null) { queue.offer(node.left); } if (node.left == null && node.right != null) { queue.offer(null); } if (node.right != null) { queue.offer(node.right); } if (node.left != null && node.right == null) { queue.offer(null); } } } return true; } /** * 递归算法 * * @param root * @return */ public static boolean isSymmetric1(TreeNode root) { if (root == null) { return true; } TreeNode left = root.left; TreeNode right = root.right; return symmetric(left, right); } private static boolean symmetric(TreeNode left, TreeNode right) { if (left == null && right == null) { return true; } if (left == null) { return false; } if (right == null) { return false; } if (left.val != right.val) { return false; } boolean x = symmetric(left.left, right.right); boolean y = symmetric(left.right, right.left); return x && y; } }
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