题解 | #二进制中1的个数#
二进制中1的个数
http://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8
Hamming Weight
class Solution {
public:
int NumberOf1(int n) {
int res = 0;
while(n!=0){
n = n&(n-1);
res++;
}
return res;
}
};
