题解 | #考试分数(三)#
考试分数(三)
http://www.nowcoder.com/practice/b83f8b0e7e934d95a56c24f047260d91
这题看出来dense_rank应该就没啥问题了
select id, name ,score
from
(select g.id,
l.name,
g.score,
dense_rank() over(partition by g.language_id order by score desc) as lang_sub_rank
from grade g
left join language l
on g.language_id = l.id) tmp
where lang_sub_rank <=2
order by name asc, score desc, id asc; 
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