题解 | #自守数#
自守数
http://www.nowcoder.com/practice/88ddd31618f04514ae3a689e83f3ab8e
import sys check_str = "0156" #位数为0,1,5,6才可能是自守数 def calc_automorphic_numbers(n): count = 0 for i in range(n+1): i_s = str(i%10) if i_s not in check_str: continue #先平方然后转成字符串,再判断是否以i结尾 if str(i**2).endswith(str(i)): count += 1 return count while True: try: n = int(input()) print(calc_automorphic_numbers(n)) except: # print(sys.exc_info()) break