swust oj1040 一元多项式的加法

#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
char ch;
void T();
void F();
void E() //E->T{+|-T@+|-} A+(B-C/D)*E
{
    char temp;
    T();
    while(ch=='+' || ch=='-')
    {
        temp=ch;
        ch=getchar();
        T();
        printf("%c",temp);
    }
}
void T() //T->F{*|/F@*|/}  A+(B-C/D)*E
{
    char temp;
    F();
    while(ch=='*' || ch=='/')
    {
        temp=ch;
        ch=getchar();
        F();
        printf("%c",temp);
    }
}
void F() //F->(E)|i@i  A+(B-C/D)*E
{
    if(ch=='(')
    {
        ch=getchar();
        E();
        if(ch!=')')
        {
            printf("need )\n");
            exit(0);
        }
        else
            ch=getchar();
    }
    else
    {
        printf("%c",ch);
        ch=getchar();
    }
} 
int main()
{
    ch=getchar();
    E();
    return 0;
}