PAT基础编程题目-7-2 然后是几点

题目详情

题目地址：https://pintia.cn/problem-sets/14/problems/782

解答

大家可能会遇到题目给的测试能通过，但提交的时候总是不通过。我这里给两个特殊的关键测试点，供大家测试和理解题目。

• 输入：1120 110 输出：1310
• 输入：1000 -588 输出：12

C语言版

#include<stdio.h>
int main() {
   
	int minute, startTime, stopTime;
	int elapsed;  //流逝的
	scanf("%d %d", &startTime, &elapsed);
	minute = (startTime / 100) * 60 + startTime % 100;  //将开始时间化为分钟
	stopTime = minute + elapsed;
	stopTime = (stopTime / 60) * 100 + stopTime % 60;  // 再把分钟化为小时
	printf("%d", stopTime);
	return 0;
}

C++版

#include<iostream>
using namespace std;
int main() {
   
	int minute, startTime, stopTime, elapsed;
	cin >> startTime >> elapsed;
	minute = (startTime / 100) * 60 + startTime % 100;
	stopTime = minute + elapsed;
	stopTime = (stopTime / 60) * 100 + stopTime % 60;
	cout << stopTime;
	return 0;
}

Java版

import java.util.Scanner;
public class Main{
   

	public static void main(String[] args) {
   
		int startTime = 0,stopTime,elapsed = 0,minute;
		Scanner scanner = new Scanner(System.in);
		if(scanner.hasNext()) {
   
			startTime = scanner.nextInt();
			elapsed = scanner.nextInt();
		}
		scanner.close();
		minute = (startTime/100)*60+startTime%100;
		stopTime = minute+elapsed;
		stopTime = (stopTime/60)*100+stopTime%60;
		System.out.println(stopTime);
	}

}

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