C++简单代码/4行/斐波那契数列：
矩形覆盖
http://www.nowcoder.com/questionTerminal/72a5a919508a4251859fb2cfb987a0e6
C++简单代码/4行/斐波那契数列：
class Solution {
public:
int rectCover(int number) {
int res = 1, res_first = 1;
for (int i = 2; i <= number; i ++)
res += res_first, res_first = res - res_first;
return (number == 0) ? 0 : res;
}
};
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