CF343D Water Tree 树链剖分
问题描述
题解
树剖,线段树维护0-1序列
yzhang:用珂朵莉树维护多好
\(\mathrm{Code}\)
#include<bits/stdc++.h>
using namespace std;
template <typename Tp>
void read(Tp &x){
x=0;char ch=1;int fh;
while(ch!='-'&&(ch<'0'||ch>'9')) ch=getchar();
if(ch=='-'){fh=-1;ch=getchar(); }
else fh=1;
while(ch>='0'&&ch<='9') x=(x<<1)+(x<<3)+ch-'0',ch=getchar();
x*=fh;
}
const int maxn=500007;
const int maxm=1000007;
int n,T;
int Head[maxn],to[maxm],Next[maxm],tot;
void add(int x,int y){
to[++tot]=y,Next[tot]=Head[x],Head[x]=tot;
}
int size[maxn],son[maxn];
int fa[maxn],dep[maxn],top[maxn],New[maxn],pre[maxn],ind;
void dfs1(int x,int f,int dp){
size[x]=1,fa[x]=f,dep[x]=dp;
int mx=-1;
for(int i=Head[x];i;i=Next[i]){
int y=to[i];
if(y==f) continue;
dfs1(y,x,dp+1);size[x]+=size[y];
if(size[y]>mx) mx=size[y],son[x]=y;
}
}
int dfn[maxn];
void dfs2(int x,int tp){
top[x]=tp,New[x]=++ind,pre[ind]=x,dfn[x]=ind;
if(!son[x]) return;
dfs2(son[x],tp);
for(int i=Head[x];i;i=Next[i]){
int y=to[i];
if(y==fa[x]||y==son[x]) continue;
dfs2(y,y);
}
dfn[x]=ind;
}
#define lfc (x<<1)
#define rgc ((x<<1)|1)
#define mid ((l+r)>>1)
int val[maxn<<2],lazy[maxn<<2];
int L,R,need;
void pushdown(int x){
lazy[lfc]=lazy[rgc]=lazy[x];val[lfc]=val[rgc]=lazy[x]-1;
lazy[x]=0;
}
void pushup(int x){
val[x]=val[lfc]+val[rgc];
}
void change(int x,int l,int r){
if(L>r||R<l) return;
if(L<=l&&r<=R){
lazy[x]=need+1,val[x]=need;return;
}
if(lazy[x]) pushdown(x);
change(lfc,l,mid);change(rgc,mid+1,r);
pushup(x);
}
int query(int x,int l,int r){
if(l==r) return val[x];
if(lazy[x]) pushdown(x);
int res;
if(L<=mid) res=query(lfc,l,mid);
else res=query(rgc,mid+1,r);
pushup(x);
return res;
}
void cz1(){
int x;read(x);
L=New[x],R=dfn[x],need=1;
change(1,1,n);
}
void cz2(){
int x,y=1;read(x);
while(top[x]!=top[y]){
if(dep[top[x]]<dep[top[y]]) swap(x,y);
L=New[top[x]],R=New[x],need=0;
change(1,1,n);
x=fa[top[x]];
}
if(dep[x]>dep[y]) swap(x,y);
L=New[x],R=New[y],need=0;
change(1,1,n);
}
void cz3(){
int x;read(x);
L=New[x];
printf("%d\n",query(1,1,n));
}
int main(){
read(n);
for(int i=1,x,y;i<n;i++){
read(x);read(y);
add(x,y);add(y,x);
}
dfs1(1,0,1);dfs2(1,1);
read(T);int op;
while(T--){
read(op);
if(op==1) cz1();
else if(op==2) cz2();
else cz3();
}
return 0;
}