PAt-A 1065. A+B and C(64bit)

Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line “Case #X: true” if A+B>C, or “Case #X: false” otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

程序代码:

#include<stdio.h>
long long a,b,c,sum;
int main()
{
    int i,T;
    scanf("%d",&T);
    for(i=1;i<=T;i++)
    {
        scanf("%lld%lld%lld",&a,&b,&c);
        sum = a+b;
        printf("Case #%d: ",i);
        if(a>0&&b>0&&sum<=0)
        {
            printf("true\n");
        }
        else if(a<0&&b<0&&sum>=0)
        {
            printf("false\n");
        }
        else if(sum>c)
        {
            printf("true\n");
        }
        else 
        {
            printf("false\n");
        }
    }
    return 0;
}
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