18.用分位数分析牛客网用户活动Nowcoder[['Num_of_exercise','Number_of_submissions']].quantile(q=0.75)多列,多个中括号19.牛客网大佬之间的差距:a=df.loc[df['Level']==7,'Achievement_value']print(a.max()-a.min())20.牛客用户刷题量的方差与提交次数的标准差:print(round(df['Num_of_exercise'].var(),2)) 方差print(round(df['Num_of_exercise'].sd(),2)) 标准差21.大佬用户成就值...