void solve(){ ll n, x, y; string a, b, c; cin >> n >> x >> y >> a >> b >> c; vector<ll> aunmatch1pos, aunmatch0pos; vector<ll> bunmatch1pos, bunmatch0pos; ll unmatched = 0, matched = 0; for(ll i = 0; i < n; i++){ ...
ylh123_：我是看剩余落点数量，如果为5，7，9必赢，很容易看出来，如果剩3，枚举任意俩个位置，如果剩1，把棋子放下去就行