//判断两个相邻字母是否在同一组按键上有其他方式 //若两相邻字母相减之差(0~3)==两相邻字母按键时间之差,则需要加上等待时间 //不过我的方法也很好 #include <iostream> using namespace std; int a[9][5]={ {0,0,0,0,0}, {0,1,2,3,0}, {0,1,2,3,0}, {0,1,2,3,0}, {0,1,2,3,0}, {0,1,2,3,0}, {0,1,2,3,4}, {0,1,2,3,0}, {0,1,2,3,4} }; int b[9][5]={ {0,0,0,0,0}, {0,1,2,3,0}, ...