给定一个字符串,请写一段代码找出这个字符串中首先出现三次的那个英文字符(需要区分大小写)。
数据范围：字符串长度满足 
[编程题]统计字符
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String ss = sc.nextLine();
int[] arr = new int [150];
int n = 0;
for(int i=65;i<=90;i++){
arr[i] = 1;
}
for(int i=97;i<=122;i++){
arr[i] = 1;
}
int index=0;
for(int j =0;j<ss.length();j++){
if(index!=0){
break;
}
arr[(int)ss.charAt(j)]+=1;
for(int i=65;i<=122;i++){
if(arr[i] == 4){
index = j;
System.out.println(ss.charAt(index));
break;
}
}
}
}
}
纯计数2333
发表于 2018-11-08 17:00:38
回复(0)
import java.util.Scanner;
import java.util.Map;
import java.util.TreeMap;
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
while(sc.hasNext()){
char[] ch = sc.nextLine().toCharArray();
Map<Character,Integer> map = new TreeMap<>();
for(int i=0;i<ch.length;i++){
if((ch[i] >='a' && ch[i]<='z') || (ch[i] >='A' && ch[i] <='Z')){
if(map.containsKey(ch[i])){
map.put(ch[i],map.get(ch[i])+1);
if(map.get(ch[i]) == 3){
System.out.println(ch[i]);
break;
}
}else{
map.put(ch[i],1);
}
}
}
}
}
}
发表于 2018-10-06 14:19:18
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import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); String string = in.nextLine(); string = string.replace(" ","").replaceAll("[^a-zA-Z0-9]",""); String[] strings = string.split(""); Map<String,Integer> map = new HashMap(); for (String s : strings) { if (!map.containsKey(s)) { map.put(s, 1); } else { map.put(s, map.get(s) + 1); if (map.containsValue(3)) { System.out.println(s); return; } } } } }
发表于 2018-09-30 15:43:58
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import java.util.HashMap;
import java.util.Scanner;
public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); while (in.hasNext()) { String string = in.nextLine(); System.out.println(threeTime(string)); } } public static char threeTime(String str) { String string = str; //除了a-zA-Z都替换为空，使得字符串只有英文字符 string = string.replaceAll("[^a-zA-Z]", ""); HashMap<Character, Integer> map = new HashMap<>(); for (int i = 0; i < string.length(); i++) { char c = string.charAt(i); if (map.containsKey(c)) { int value = map.get(c); if (value - 2 == 0) { return c; } else { map.put(c, ++value); } } else { map.put(c, 1); } //System.out.println(c + "===" + map.get(c)); } return '#'; }
}
发表于 2018-09-18 21:06:15
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import java.util.Scanner;
public class Main{
public static void main(String []args){
Scanner sc=new Scanner(System.in);
String str=sc.nextLine().replace(" ","");
int []s=new int[127];
for(int i=0;i<str.length();i++){
s[str.charAt(i)]++;
if(s[str.charAt(i)]==3&&(str.charAt(i)>='a'&&str.charAt(i)<='z'||str.charAt(i)>='A'&&str.charAt(i)<='Z')){
char c=str.charAt(i);
System.out.println(c);
break;}
}
}
}
编辑于 2018-09-07 14:06:56
回复(0)
因为要区分大小写，26个大写，26个小写字母，因此维护一个大小为52的数组，来保存该字母出现的次数，遍历循环整个字符串，统计每个字符出现的次数，当出现次数为3时则找到了该字符，并跳出循环。
import java.util.Scanner;
public class CountChar {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc = new Scanner(System.in);
String str = sc.nextLine().trim();
char[] strs = str.toCharArray();
int[] charCount = new int[52];
for(int i=0; i<strs.length; i++) {
if(strs[i] != ' ') {
if(strs[i]>='A' && strs[i]<='Z') {
charCount[strs[i] - 'A'] ++;
if(charCount[strs[i] - 'A']==3) {
System.out.println(strs[i]);
break;
}
}else if(strs[i]>='a' && strs[i]<='z') {
charCount[strs[i] - 'a' + 26] ++;
if(charCount[strs[i] - 'a' + 26]==3) {
System.out.println(strs[i]);
break;
}
}
}
}
}
}
发表于 2018-08-29 21:36:34
回复(0)
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
if (in.hasNext()) {
String str = in.nextLine();
System.out.println(threetimes(str));
}
}
public static String threetimes(String str) {
String[] zimu = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "g", "k", "l", "m", "n", "o", "p", "q", "r", "s",
"t", "u", "v", "w", "x", "y", "z" };
int[] lnumber = new int[26];
int[] unumber = new int[26];
for (int i = 0; i < str.length(); i++) {
String s = str.substring(i, i + 1);
for (int j = 0; j < zimu.length; j++) {
if (s.equals(zimu[j])) {
lnumber[j]++;
if (lnumber[j] == 3) {
return zimu[j];
}
} else if (s.toLowerCase().equals(zimu[j])) {
unumber[j]++;
if (unumber[j] == 3) {
return zimu[j].toUpperCase();
}
}
}
}
return null;
}
}
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
if (in.hasNext()) {
String str = in.nextLine();
System.out.println(threetimes(str));
}
}
public static String threetimes(String str) {
String[] zimu = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "g", "k", "l", "m", "n", "o", "p", "q", "r", "s",
"t", "u", "v", "w", "x", "y", "z" };
int[] lnumber = new int[26];
int[] unumber = new int[26];
for (int i = 0; i < str.length(); i++) {
String s = str.substring(i, i + 1);
for (int j = 0; j < zimu.length; j++) {
if (s.equals(zimu[j])) {
lnumber[j]++;
if (lnumber[j] == 3) {
return zimu[j];
}
} else if (s.toLowerCase().equals(zimu[j])) {
unumber[j]++;
if (unumber[j] == 3) {
return zimu[j].toUpperCase();
}
}
}
}
return null;
}
}
发表于 2018-04-10 15:13:02
回复(0)
import java.util.*;
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
Map<Character,Integer> values = new HashMap();
char target = '\0';
String vals = sc.nextLine();
for(int i = 0;i<vals.length();i++){
char c = vals.charAt(i);
if(!String.valueOf(c).matches("[a-zA-Z]")){//去除非英文字母
continue;
}
if(values.containsKey(c)){
int val = values.get(c);
if(++val==3){
target = c;
break;
}else{
values.put(c,val);
}
}else{
values.put(c,1);
}
}
System.out.println(target);
}
}
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
Map<Character,Integer> values = new HashMap();
char target = '\0';
String vals = sc.nextLine();
for(int i = 0;i<vals.length();i++){
char c = vals.charAt(i);
if(!String.valueOf(c).matches("[a-zA-Z]")){//去除非英文字母
continue;
}
if(values.containsKey(c)){
int val = values.get(c);
if(++val==3){
target = c;
break;
}else{
values.put(c,val);
}
}else{
values.put(c,1);
}
}
System.out.println(target);
}
}
发表于 2018-03-27 17:36:47
回复(0)
竟然有坑
- 要求输出结果是英文字符
- 出现次数是大于等于3，而非正好等于3
import java.util.LinkedHashMap;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (in.hasNext()) {
String s = in.nextLine();
count(s);
}
}
private static void count(String s) {
LinkedHashMap map = new LinkedHashMap();
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
if (map.containsKey(c)) {
if (map.get(c) == 2 && Character.toUpperCase(c) >= 'A' && Character.toUpperCase(c) <= 'Z') {
System.out.println(c);
break;
}
map.put(c, map.get(c) + 1);
} else {
map.put(c, 1);
}
}
}
}
编辑于 2018-03-26 17:03:16
回复(0)
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
String line = reader.readLine();
System.out.println(search(line));
}
private static char search(String str) {
int[] counts = new int[128];
for (int i = 0; i < str.length(); i++) {
char c = str.charAt(i);
if (c >= 'A' && c <= 'z') {
int index = c - 'A';
counts[index] += 1;
if (counts[index] == 3) {
return c;
}
}
}
return ' ';
}
}
发表于 2018-01-26 22:27:01
回复(0)
//看清题目：字符串包括字母、数字等，但统计的是字母
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (in.hasNext()) {
String string = in.nextLine();
int[] chs = new int[256];
for (int i = 0; i < string.length(); i++) {
if (Character.isAlphabetic(string.charAt(i))) {
chs[string.charAt(i)]++;
if (chs[string.charAt(i)] == 3) {
System.out.println(string.charAt(i));
break;
}
}
}
}
}
}
编辑于 2017-12-25 22:12:25
回复(0)
import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner scanner = new Scanner(System.in); while (scanner.hasNext()) { String str = scanner.nextLine(); Map<Character, Integer> properties = new HashMap<>(); int countc; for (int i = 0; i < str.length(); i++) { if (properties.containsKey(str.charAt(i))) { countc = properties.get(str.charAt(i)) + 1; properties.put(str.charAt(i), countc); if (countc == 3 && ((str.charAt(i) >= 65 && str.charAt(i) <= 90) || (str.charAt(i) >= 97 && str.charAt(i) <= 122))) { System.out.println(str.charAt(i)); break; } } else { properties.put(str.charAt(i), 1); } } } } }这个题感觉最重要的就是要理解题意，我理解错了两次，第一个注意点就是输入的字符串不只是英文字母，还可能是别的字符，第二个注意点就是要输出的是第一次出现三次的英文字母，而不是任意字符。理解题意很重要，其次就是数据结构，我用的是一个Map结构，把出现的字符，以及这个字符的出现次数存了起来，出现三次的英文字母后就结束循环。
发表于 2017-11-28 21:00:54
回复(0)
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNextLine()) {
char[] arr = sc.nextLine().replaceAll("[^a-zA-Z]", "").toCharArray();
Map<Character, Integer> map = new HashMap<>();
for (int i = 0; i < arr.length; i ++) {
map.put(arr[i], map.containsKey(arr[i]) ? map.get(arr[i]) + 1 : 1);
if(map.get(arr[i]) == 3) {
System.out.println(arr[i]);
break;
}
}
}
}
}
发表于 2017-11-20 23:29:43
回复(0)
import java.util.HashMap;
import java.util.Scanner;
// 哪里不对求指教
/**
- @author AmVilCres
@desc
*/
public class ThirdWord {
public static void main(String[] args) {//System.out.println(">".toLowerCase().equals(">")); Scanner sc = new Scanner(System.in); String str = sc.nextLine(); sc.close(); str = str.replaceAll(" +", ""); //System.out.println(str); char[] chs = str.toCharArray(); HashMap<String,Integer> map = new HashMap<>(); for(char c :chs) { if(map.get((c+"").toLowerCase())==null) { map.put((c+"").toLowerCase(), 1); }else { map.put((c+"").toLowerCase(), map.get((c+"").toLowerCase())+1); } if(map.get((c+"").toLowerCase()) == 3) { System.out.println(c); break; } }}
}
编辑于 2017-11-01 17:54:59
回复(0)
importjava.util.HashMap;
importjava.util.Map;
importjava.util.Scanner;
/**
* @author jiaqing.xu@hand-china.com
* @version 1.0
* @name
* @description 给定一个英文字符串, 请写一段代码找出这个字符串中首先出现三次的那个英文字符。
* @date 2017/10/15
*/
publicclassMain {
publicstaticvoidmain(String[] args) {
Scanner sc = newScanner(System.in);
String str = sc.nextLine();
//map中存放字符和对应的出现次数
Map<Character, Integer> map = newHashMap();
//将字符串转换为字符数组
char[] temp = str.toCharArray();
for(inti = 0; i < temp.length; i++) {
//判断是否为字符
if((!(temp[i] >= 'a'&& temp[i] <= 'z')) && (!(temp[i] >= 'A'&& temp[i] <= 'Z'))) {
continue;//进入下次循环
} else{
if(!map.containsKey(temp[i])) {//不包含则初始为1
map.put(temp[i], 1);
} else{//包含情况
intcount = map.get(temp[i]) + 1;//如果包含数目+1
if(count == 3) {
System.out.println(temp[i]);
break;//退出循环
}
map.put(temp[i], count);
}
}
}
}
}
发表于 2017-10-15 20:37:04
回复(0)
import java.util.*;
public class Main{
public static void main(String[] atgs){
Scanner sc = new Scanner(System.in);
int[] d = new int[256];
String s = sc.nextLine();
char[] a = s.toCharArray();
for(char c:a){
if((c>='a'&&c<='z')||(c>='A'&&c<='Z')){
d[c]++;
if(d[c]==3){
System.out.print(c);
return;
}
}
}
}
}
发表于 2017-09-22 13:58:47
回复(0)
问题信息
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