请设计一个算法,给一个字符串进行二进制编码,使得编码后字符串的长度最短。
数据范围:字符串长度满足 ,本题有多组输入
哈夫曼编码:1.按照字符词频建立小根堆。2. 每次找2个出现次数最少的字符,统计出现次数(对于其当前编码长度),再将两字符词频相加作为新字符的词频放入小根堆,直到小根堆中不足2个元素,结束。
假如, 字符a和字符b的词频出现次数最少,其编码后缀为0和1,把‘ab’作为新字符加入小根堆,按照此过程可以得到‘ab’的编码(假如为111),则字符a和字符b的完成编码为‘1110’ 和‘1111’。
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while(sc.hasNext()) { char[] ch = sc.next().toCharArray(); Map map = new HashMap(); for(int i=0; i < ch.length; i++) map.put(ch[i], map.getOrDefault(ch[i], 0) + 1); PriorityQueue q = new PriorityQueue(); for(int value : map.values()) q.offer(value); int res = 0; while(q.size() >= 2) { int a = q.poll(), b = q.poll(); res += a + b; q.offer(a+b); } System.out.println(res); } } }
package NewCoder.XiaoZhaoZhenTi; import java.util.ArrayList; import java.util.Collections; import java.util.HashMap; import java.util.HashSet; import java.util.Iterator; import java.util.Map; import java.util.Map.Entry; import java.util.Scanner; import java.util.Set; public class test3_7 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while(scanner.hasNext()){ map2.clear(); String string = scanner.nextLine(); char[] chars = string.toCharArray(); Map<String,Integer> mapx = new HashMap<>(); for(int i = 0 ; i < chars.length ; i ++){ String temp = String.valueOf(chars[i]); if(mapx.containsKey(temp)){ mapx.put(temp,mapx.get(temp)+1); }else{ mapx.put(temp, 1); } } ArrayList<Integer> numList1 = new ArrayList<>(); Iterator<Entry<String, Integer>> iterator = mapx.entrySet().iterator(); while(iterator.hasNext()){ Integer xInteger = iterator.next().getValue(); numList1.add(xInteger); } Collections.sort(numList1); //对数字排序一次,方便以后找两个最小值 ArrayList<TreeNode> numList = new ArrayList<>(); for(int i = 0 ; i < numList1.size() ; i ++){ numList.add(new TreeNode(numList1.get(i))); //得到所有字符出现次数的树节点 } if(numList.size()<=2){ System.out.println(numList.size()); continue; } Set<TreeNode> set = new HashSet<>(); TreeNode root = null; //构建哈夫曼树 while(numList.size() !=1){ TreeNode xNode = numList.remove(0);//当前最小的 TreeNode yNode = numList.remove(0);//当前第二小 TreeNode sumNode = new TreeNode(xNode.value+yNode.value); int isadd = 0; for(int i = 0 ; i < numList.size() ; i++){ if(numList.get(i).value > sumNode.value){ numList.add(i, sumNode); //把新合并的节点插到list里,注意保持递增顺序 isadd = 1; break; } } if(isadd == 0){ numList.add(sumNode); } set.add(sumNode); sumNode.left = xNode; sumNode.right = yNode; root = sumNode; //构建新节点的左右子节点 } fun(root, 0); //计算所有的叶子结点的深度 Iterator<Entry<TreeNode, Integer>> iterator2 = map2.entrySet().iterator(); int result = 0; while(iterator2.hasNext()){ Entry<TreeNode, Integer> entry = iterator2.next(); result += entry.getKey().value*entry.getValue();//所有叶子结点深度*值 之和 } System.out.println(result); } } static Map<TreeNode, Integer> map2 = new HashMap<>(); //计算所有的叶子结点的深度 static void fun(TreeNode root,int length){ if(root.left == null && root.right == null){ map2.put(root, length); return; }else{ if(root.left!=null){ fun(root.left, length+1); } if(root.right!=null){ fun(root.right, length+1); } } } } class TreeNode{ int value ; TreeNode left = null; TreeNode right = null; public TreeNode(int value) { super(); this.value = value; } public TreeNode getLeft() { return left; } public void setLeft(TreeNode left) { this.left = left; } public TreeNode getRight() { return right; } public void setRight(TreeNode right) { this.right = right; } }
import java.util.*; public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); while (input.hasNext()) { String s = input.nextLine(); int result = hafuman(s); System.out.println(result); } } public static int hafuman(String s) { char[] chars = s.toCharArray(); //hash表存放每个字符和出现的次数 Map<Character, Integer> hash = new HashMap<>(); for (int i = 0; i < chars.length; i++) { if (hash.containsKey(chars[i])) { hash.put(chars[i], hash.get(chars[i]) + 1); } else { hash.put(chars[i], 1); } } //优先队列(最小推),每次能得到weigh最小的node Queue<TreeNode> q = new PriorityQueue<>(hash.size(), new Comparator<TreeNode>() { @Override public int compare(TreeNode o1, TreeNode o2) { return Integer.compare(o1.weight, o2.weight); } }); for (Map.Entry<Character, Integer> entry : hash.entrySet()) { q.offer(new TreeNode(entry.getValue(), entry.getKey())); } while (q.size() > 1) { //弹出两个最小的,合并为一个node TreeNode left = q.poll(); TreeNode right = q.poll(); TreeNode father = new TreeNode(left.weight + right.weight); father.left = left; father.right = right; q.offer(father); } TreeNode root = q.poll(); //计算长度 return valLength(root, 0); } public static int valLength(TreeNode node, int depth) { if (node == null) return 0;//仅计算ch有值的 return (node.ch == null ? 0 : node.weight) * depth + valLength(node.left, depth + 1) + valLength(node.right, depth + 1); } static class TreeNode { int weight;//权重,出现次数 Character ch;//如果是初始字符,则ch为字符,如果是合并的,则为null TreeNode left; TreeNode right; public TreeNode(int weight) { this.weight = weight; } public TreeNode(int weight, Character ch) { this.weight = weight; this.ch = ch; } } }
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while (sc.hasNext()) { String s = sc.nextLine(); Map<Character, Integer> map = new HashMap<>(); for (int i = 0; i < s.length(); i ++) { char key = s.charAt(i); map.put(key, map.containsKey(key) ? map.get(key) + 1 : 1); } PriorityQueue<Node> queue = new PriorityQueue<>(); for (Character c:map.keySet()) { queue.add(new Node(map.get(c))); } Node root = null; while (queue.size() != 1) { Node left = queue.poll(); Node right = queue.poll(); root = new Node(left.value + right.value); root.left = left; root.right = right; queue.add(root); } System.out.println(countLength(root, 0)); } } public static int countLength(Node root, int level) { if(root.left == null && root.right == null) return root.value * level; return countLength(root.left, level + 1) + countLength(root.right, level + 1); } static class Node implements Comparable<Node> { private int value; private Node left; private Node right; public Node(int value) { this.value = value; } @Override public int compareTo(Node o) { return this.value - o.value; } } }