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Graduate Admission

[编程题]Graduate Admission
  • 热度指数:2014 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 64M,其他语言128M
  • 算法知识视频讲解
It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure.
Each applicant will have to provide two grades: the national entrance exam grade GE , and the interview grade GI . The final grade of an applicant is (GE + GI ) / 2. The admission rules are:

  • The applicants are ranked according to their final grades, and will be admitted one by one from the top of the rank list.
  • If there is a tied final grade, the applicants will be ranked according to their national entrance exam grade GE. If still tied, their ranks must be the same.
  • Each applicant may have K choices and the admission will be done according to his/her choices: if according to the rank list, it is one's turn to be admitted; and if the quota of one's most preferred shcool is not exceeded, then one will be admitted to this school, or one's other choices will be considered one by one in order. If one gets rejected by all of preferred schools, then this unfortunate applicant will be rejected.
  • If there is a tied rank, and if the corresponding applicants are applying to the same school, then that school must admit all the applicants with the same rank, even if its quota will be exceeded.

  • 输入描述:
    Each input file contains one test case.  Each case starts with a line containing three positive integers: N (<=40,000), the total number of applicants; M (<=100), the total number of graduate schools; and K (<=5), the number of choices an applicant may have.
    In the next line, separated by a space, there are M positive integers. The i-th integer is the quota of the i-th graduate school respectively.
    Then N lines follow, each contains 2+K integers separated by a space. The first 2 integers are the applicant's GE and GI, respectively. The next K integers represent the preferred schools. For the sake of simplicity, we assume that the schools are numbered from 0 to M-1, and the applicants are numbered from 0 to N-1.


    输出描述:
    For each test case you should output the admission results for all the graduate schools.  The results of each school must occupy a line, which contains the applicants' numbers that school admits.  The numbers must be in increasing order and be separated by a space.  There must be no extra space at the end of each line.  If no applicant is admitted by a school, you must output an empty line correspondingly.
    示例1

    输入

    11 6 3
    2 1 2 2 2 3
    100 100 0 1 2
    60 60 2 3 5
    100 90 0 3 4
    90 100 1 2 0
    90 90 5 1 3
    80 90 1 0 2
    80 80 0 1 2
    80 80 0 1 2
    80 70 1 3 2
    70 80 1 2 3
    100 100 0 2 4

    输出

    0 10
    3
    5 6 7
    2 8
    
    1 4
    头像 wbc990512
    发表于 2021-01-25 23:31:22
    题意:根据学生的成绩和排名,根据学校的招生情况,确定最终的招生结果。输入N,M,K,代表N个学生,M个学校,每个学生有K种志愿(可以相同)接下来的一行输入M个整数,代表这M个学校的最多录取人数接下来的N行,每一行输入2+K个数,分别代表学生的GE(高考成绩)、GI(面试成绩)、K个志愿录取规则:(1 展开全文
    头像 GoodLunatic
    发表于 2024-08-20 14:03:21
    #include <bits/stdc++.h> using namespace std; priority_queue<int, vector<int>, greater<int> > output; const int N = 40010; in 展开全文
    头像 cyber1026
    发表于 2024-03-03 16:53:45
    #include <iostream> #include <algorithm> #include <vector> using namespace std; struct school{ int quota; int fact; int ge; int 展开全文
    头像 Moyoj
    发表于 2024-03-07 10:27:28
    #include <iostream> #include<algorithm> #include <vector> using namespace std; struct ApplicantInfo{ int id; int rank; i 展开全文