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根据题目要求写出sql

[问答题]

在SQL中，一个表的定义如下：

CREATE TABLE t_account(
     account varchar(100),
     account_type TINYTEXT,
     PRIMARY KEY (account),
};

account为账号，account_type为该账号的类型，写出一个sql，统计账号数累计超过5000个账号类型，并显示对应的账号数，即结果中每行是（账号类型，账号数）

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咨诹善道

SELECT account_type,COUNT(account_type)

FROM t_account

GROUP BY account_type

HAVING COUNT ( account_type )>5000;

编辑于 2015-04-25 23:05:19 回复(3)

虾小姐与娃哈哈

select account_type as 账号类型，count(account) as 账号数 from t_account group by account_type having count(account)>5000

发表于 2015-06-25 14:27:58 回复(0)

allinallin

select account_type, count(*)

from t_account

group by account_type

having count(*)>5000

发表于 2016-03-22 16:15:20 回复(0)

hehehaha

select account_type 账号类型，count(account)  账号数 from t_account group by account_type having count(account)>5000

发表于 2015-10-06 13:50:05 回复(0)

飞龙在天的副

<div> select  account_type count(*) </div> <div> from t_account </div> <div> group by <span>account_type</span> </div> <div> <span>having count(*) > 50000</span> </div>

发表于 2015-09-09 20:53:54 回复(0)

待定-莫

select account_type，count(account) from t_account group by account having count(account)>5000

编辑于 2015-07-28 16:14:59 回复(0)

不想抄作业的米老鼠

select account_type AS 账号类型,count(*) AS 帐号数 from t_account
group by account_type
having count(*) > 5000

发表于 2015-05-17 13:48:34 回复(0)

771405525

select account_type, count(*) from t_account group by account_type having count(*) > 5000;

发表于 2015-05-03 21:17:34 回复(0)

ToExplore

select account_type, count(*) from t_account group by account_type having count(*) > 5000

发表于 2015-04-30 15:50:20 回复(0)

AlisaLin_60078

select account_type, count(*)

from t_account

group by account_type

having count(*) > 5000;

发表于 2015-04-30 15:38:07 回复(0)

sherlockruu

SELECT account_type, count(*)
FROM t_account
GROUP BY account_type
HAVING COUNT(*) > 5000;

发表于 2015-04-30 09:48:22 回复(0)

Ivanyooh

select account_type 账号类型,count(account) 账号数 from t_account group by account_type having count(account)>5000

发表于 2015-04-29 00:30:45 回复(0)

rode

select account_type,count(1) as count from t_account group by account_type having count > 5000;

发表于 2015-04-26 23:03:19 回复(0)

╰疯人疯愿≯疯心

select account_type 帐号类型,count(account) 帐号数 from t_account where account_type in (select account_type from t_account where count(account_type)>5000)

发表于 2015-04-26 17:30:43 回复(0)

东大的

select account_type,count(account) from t_account group by account_type having count(account_type)>5000

发表于 2015-04-26 16:12:10 回复(0)

maomao毛毛虫

select account_type,count(account) from t_account group by account_type having count(account_type)>5000;

发表于 2015-04-25 22:46:21 回复(0)

lxzmtb

select account_type,count(account) from t_account groupby account_type having count(account)>5000;

发表于 2015-04-25 10:03:14 回复(0)

峡岢

select account_type,count(account_type)

from t_account

group by account_type

having count(account_type)>5000

发表于 2015-04-25 00:46:57 回复(0)

焰殊

select account_type,count(account_type)

from t_account

group by account

having count(account_type)>5000

发表于 2015-04-25 00:35:48 回复(0)

F@N

select account_type,count(account_type)

from t_account

group by account_type

having count(account_type)>5000

发表于 2015-04-25 00:09:41 回复(0)

nersie78

SELECT account_type , count ( account ) FROM `t_account` group by account_type HAVING count ( * ) > 5000

发表于 2015-04-24 23:32:04 回复(0)

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问题信息

网易网易互娱游戏研发工程师 2015 数据库

来自：2015网易互娱校园招...

上传者：小牧魔法袋

难度：

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根据题目要求写出sql

问题信息

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