对字符串中的所有单词进行倒排。
说明：
1、构成单词的字符只有26个大写或小写英文字母；
2、非构成单词的字符均视为单词间隔符；
3、要求倒排后的单词间隔符以一个空格表示；如果原字符串中相邻单词间有多个间隔符时，倒排转换后也只允许出现一个空格间隔符；
4、每个单词最长20个字母；
数据范围：字符串长度满足 
[编程题]单词倒排
#include<string>
#include<iostream>
#include<vector>
#include<algorithm>
#include<cstring>
#include<cctype>
using namespace std;
int main()
{
string str;
getline(cin,str);
vector<string> vec;
int begin = 0;
int len = 0;
bool renew_begin = true;
for(int i = 0; i <str.length(); i++)
{
if((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z'))
{
len++;
if(renew_begin)
{
begin = i;
renew_begin = false;
}
if(i == str.length()-1)
{
string temp = str.substr(begin,len);
vec.push_back(temp);
break;
}
}
else
{
if(len>=1)
{
string temp = str.substr(begin,len);
vec.push_back(temp);
renew_begin = true;
len = 0;
}
}
}
reverse(vec.begin(), vec.end());
for(auto it = vec.begin(); it != vec.end(); it++)
{
if(it<vec.end()-1)
cout<<*it<<" ";
else
cout<<*it;
}
cout<<endl;
return 0;
}
发表于 2019-02-20 12:22:01
回复(2)
while True:
try:
s = input().split()
res = []
for i in s:
t = []
i = list(i)
for j in i:
if j.isalpha():
t.append(j)
else:
t.append(" ")
t = "".join(t).split()
res.extend(t)
res = res[::-1]
for i in res:
print(i,end=" ")
except:
break
发表于 2022-01-04 11:18:13
回复(0)
比之前的句子逆序多一步判断是不是字母
#include<bits/stdc++.h>
using namespace std;
int main()
{
string x;
while(getline(cin,x))
{
int i;
for(i=0;i<x.size();i++)
{
if(!((x[i]>='a'&&x[i]<='z')||(x[i]>='A'&&x[i]<='Z')))
x[i]=' ';//判断是不是字母，不是就替换成空格
}
string a;
while(x.find_last_of(' ')!=-1)//找到最后一个空格，输出之后的字符串
{
a=x.substr(x.find_last_of(' ')+1);
cout<<a<<" ";
x=x.substr(0,x.find_last_of(' '));
}
cout<<x<<endl;
}
return 0;
}
编辑于 2021-09-22 15:35:03
回复(0)
import java.io.BufferedReader;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s = br.readLine();
StringBuilder sb = new StringBuilder();
int len = s.length(), i = len - 1, j = i+1;
while (i > -1) {
while (i > -1 && Character.isLetter(s.charAt(i))) i--;
sb.append(s, i + 1, j).append(' ');
j = i;
while (i > -1 && !Character.isLetter(s.charAt(i))) i--;
}
System.out.println(sb.toString().trim());
}
}
发表于 2021-09-14 14:58:32
回复(0)
#include <iostream>
#include <string>
#include <vector>
using namespace std;
// 修改了上述一个答案，测试用例全部通过
int main()
{
string str;
while (getline(cin, str))
{
vector<string> array;
string temp;
// 这里i一定要<=str.size()
// 因为走到最后的'\0'，才会进入else，将最后一部分单词push到array中
for (int i = 0; i <= str.length(); i++)
{
if (isalpha(str[i]) && str[i] != '\0')
temp += str[i];
else
{
if (temp == "")
continue;
array.push_back(temp);
temp.clear();
}
}
for (int i = array.size() - 1; i >= 0; i--)
cout << array[i] << ' ';
cout << endl;
}
return 0;
}
编辑于 2021-06-15 09:22:10
回复(0)
while True:
try:
s=list(raw_input().split())
nn=""
ll=[]
l=[]
for i in range(len(s)):
ls=list(s[i])
#print(ls)
x=len(ls)
mm=[]
for j in range(x):
#print(j)
if ls[j].isalpha():
mm.append(ls[j])
else:
mm.append(" ")
ss="".join(mm)
ss.strip()
l=list(ss.split())
for i in l:
ll.append(i)
ll=ll[::-1]
print(" ".join(ll))
except:
break
发表于 2019-07-12 20:31:15
回复(0)
#include<iostream>
#include<string>
#include<algorithm>
using namespace std;
int main()
{
string inn;
while(getline(cin,inn))
{
string str;
for(char temp:inn)
{
if((temp<='Z'&&temp>='A')||(temp<='z'&&temp>='a'))
str += temp;
else if(str.length()>0&&str.back()!=' ')
str += ' ';
}
// ==================== 注意 =====================
// 末尾可能有空格,要删除,90%的通过率就是这里的问题.
// ===============================================
if(str.back()==' ')
//str.erase(str.end()-1);
str.erase(str.length()-1);
int start = 0;
while(1)
{
int ind = str.find(' ',start);
if(ind>=0)
reverse(str.begin()+start,str.begin()+ind);
else
{
reverse(str.begin()+start,str.end());
break;
}
start = ind+1;
}
reverse(str.begin(),str.end());
if(str.length()==0)
cout<<' '<<endl;
else
cout<<str<<endl;
}
return 0;
}
发表于 2018-08-15 11:23:02
回复(0)
#include <iostream>
#include <string.h>
using namespace std;
char str[10000];
char dic[10000][22];
int main()
{
while(gets(str))
{
int flag = 0;//判断是否是第一个空格
int len = strlen(str), it = 0, Word = 0;//单词个数
for(int i=0;i<len;i++)
{
if((str[i]>='a'&&str[i]<='z') || (str[i]>='A'&&str[i]<='Z'))
{
flag = 1;
dic[Word][it++] = str[i];
}
else
{
if(flag == 1)
{
dic[Word][it] = '\0';
it = 0;
Word++;
flag = 0;
}
}
}
dic[Word][it] = '\0';
for(int i=Word;i>=0;i--)
{
if(dic[i][0]!='\0')//他可能出现句首不是字母的情况
{
cout<<dic[i];
if(i)
cout<<" ";
}
}
cout<<endl;
}
return 0;
}
发表于 2017-02-01 00:31:01
回复(2)
import java.util.Scanner;
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
while(sc.hasNextLine()){
String str = sc.nextLine();
String[] rs = str.split("[^a-zA-Z]");
String[] b = new String[rs.length];
for(int i = rs.length-1 ; i >= 0 ; i--){
b[rs.length-1-i] = rs[i];
System.out.print(b[rs.length-1-i] + " ");
}
}
}
}
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
while(sc.hasNextLine()){
String str = sc.nextLine();
String[] rs = str.split("[^a-zA-Z]");
String[] b = new String[rs.length];
for(int i = rs.length-1 ; i >= 0 ; i--){
b[rs.length-1-i] = rs[i];
System.out.print(b[rs.length-1-i] + " ");
}
}
}
}
发表于 2021-11-04 15:41:04
回复(0)
import java.io.BufferedReader;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws Exception {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String[] str = br.readLine().split("[^A-Za-z]+");
int length = str.length;
StringBuilder sb = new StringBuilder();
for (int i = length - 1;i >= 0;i--){
sb.append(str[i] + " ");
}
System.out.println(sb.toString().trim());
}
}
发表于 2022-07-14 15:24:46
回复(0)
<?php
$str = trim(fgets(STDIN));
preg_match_all("/([a-zA-Z]+)/", $str, $matchs);
echo implode(' ', array_reverse($matchs[0]));
?>
$str = trim(fgets(STDIN));
preg_match_all("/([a-zA-Z]+)/", $str, $matchs);
echo implode(' ', array_reverse($matchs[0]));
?>
发表于 2022-07-06 12:42:07
回复(0)
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
List<String> list = new ArrayList<>();
StringBuilder sb = new StringBuilder();
for(int i=0;i<s.length();i++){
char ch = s.charAt(i);
int j = i;
while((ch>='a' && ch<='z') || (ch>='A' && ch<='Z')){
j++;
if(j>=s.length()) break;
ch = s.charAt(j);
}
if(j>i){
list.add(s.substring(i,j));
}
i=j;
}
for(int i=list.size()-1;i>=1;i--){
sb.append(list.get(i));
sb.append(' ');
}
sb.append(list.get(0));
System.out.println(sb.toString());
}
}
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
List<String> list = new ArrayList<>();
StringBuilder sb = new StringBuilder();
for(int i=0;i<s.length();i++){
char ch = s.charAt(i);
int j = i;
while((ch>='a' && ch<='z') || (ch>='A' && ch<='Z')){
j++;
if(j>=s.length()) break;
ch = s.charAt(j);
}
if(j>i){
list.add(s.substring(i,j));
}
i=j;
}
for(int i=list.size()-1;i>=1;i--){
sb.append(list.get(i));
sb.append(' ');
}
sb.append(list.get(0));
System.out.println(sb.toString());
}
}
发表于 2022-05-23 10:46:01
回复(0)
n=input()
for i in range(len(n)):
if not n[i].isalpha():
n=n.replace(n[i], ' ')
list=n.split(' ')
list.reverse()
for i in list:
print(i,end=' ')
发表于 2022-05-17 20:24:40
回复(0)
/*** 2/26
一、思路
1.将非大小写字母的char全部替换成空格
注意：只能用replace() 不能用replaceAll()
2.用split(" ")将string分隔进String[]
3.倒序输出
二、匹配非字母的字符进行分割
1.我的思路：将非字母字符全部替换成空格，再用空格分隔
2.其他：正则表达式[^a-zA-Z]分割：String[] words = str.split("[^A-Za-z]");
三、一些比较：
str = str.replace(String.valueOf(c)," ")时，运行时间:134ms，占用内存:17400KB
改为str = str.replace(c,' ')后 运行时间:48ms，占用内存:11548KB，提升30%多
四、知识点：replace() 与 replaceAll()
1.String replace(char oldChar, char newChar)
返回一个新的字符串，它是通过用 newChar 替换此字符串中出现的所有 oldChar 得到的。
2.String replaceAll(String regex, String replacement)
使用给定的 replacement 替换此字符串所有匹配给定的正则表达式的子字符串。
3.replaceAll用的是正则，replace用的是字符，二者都能替换*所有*匹配的字符
示例：
String str = "hello.hello.hello";
System.out.println(str.replace(".","#")); //hello#hello#hello
System.out.println(str.replaceAll(".","#")); //#################
System.out.println(str.replaceAll("\\.","#")); //hello#hello#hello
***/
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
String str = sc.nextLine();
char[] chs = str.toCharArray();
for(char c : chs){
if(!Character.isLetter(c)){
str = str.replace(c,' ');
}
}
String[] strArr = str.split(" ");
for(int i = strArr.length-1; i>=0; i-- ){
System.out.print(strArr[i] + " ");
}
}
}
}
发表于 2022-05-05 16:14:40
回复(0)
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
String[] strArr = sc.nextLine().split(" ");
StringBuilder sb = new StringBuilder();
for (int i = strArr.length - 1; i >= 0; i--) {
StringBuilder temp = new StringBuilder();
for (char ch : strArr[i].toCharArray()) {
if (Character.isLetter(ch)) {
temp.append(ch);
} else {
temp.append(" ");
}
}
String tempStr = temp.toString();
if (tempStr.contains(" ")) {
String[] tempArr = tempStr.split(" ");
for (int j = tempArr.length - 1; j >= 0 && tempArr[j].length() > 0; j--) {
sb.append(tempArr[j] + " ");
}
} else {
sb.append(tempStr + " ");
}
}
System.out.println(sb.substring(0, sb.length() - 1));
}
}
}
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
String[] strArr = sc.nextLine().split(" ");
StringBuilder sb = new StringBuilder();
for (int i = strArr.length - 1; i >= 0; i--) {
StringBuilder temp = new StringBuilder();
for (char ch : strArr[i].toCharArray()) {
if (Character.isLetter(ch)) {
temp.append(ch);
} else {
temp.append(" ");
}
}
String tempStr = temp.toString();
if (tempStr.contains(" ")) {
String[] tempArr = tempStr.split(" ");
for (int j = tempArr.length - 1; j >= 0 && tempArr[j].length() > 0; j--) {
sb.append(tempArr[j] + " ");
}
} else {
sb.append(tempStr + " ");
}
}
System.out.println(sb.substring(0, sb.length() - 1));
}
}
}
发表于 2022-04-19 19:57:13
回复(0)
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while(sc.hasNextLine()){
String content = sc.nextLine();
content.trim();
char[] ch = content.toCharArray();
String newContent = "";
if(Character.isLetter(ch[0])){
newContent += ch[0];
}
for(int i = 1;i < ch.length ; i++){
if(Character.isLetter(ch[i])){
newContent += ch[i];
}else{
if(Character.isLetter(ch[i-1])){
newContent += " ";
}
}
}
String[] strArray = newContent.split(" ");
for(int i = strArray.length-1;i >= 0;i--){
System.out.print(strArray[i]+" ");
}
System.out.println();
}
}
}
发表于 2021-11-28 22:22:51
回复(0)
package main
import (
"bufio"
"fmt"
"os"
)
func main(){
// 读取终端输入
var scanner = bufio.NewScanner(os.Stdin)
scanner.Scan()
var str = scanner.Text()
// 逆序打印，如果非字母只打印空格
var slice []string
var tempStr = ""
for i:=0;i<len(str);i++ {
if (str[i] >= 97 && str[i] <= 122) || (str[i] >= 65 && str[i] <= 90) {
tempStr = tempStr + string(str[i])
if i == len(str) -1 {
slice = append(slice, tempStr)
}
}else {
slice = append(slice, tempStr)
tempStr = ""
}
}
for i:=len(slice)-1;i>=0;i-- {
fmt.Printf("%v ",slice[i])
}
}
发表于 2021-11-07 10:42:49
回复(0)
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