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简单密码

[编程题]简单密码

热度指数：311324 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 32M，其他语言64M
算法知识视频讲解

$\hspace{15pt}$ 规定这样一种密码的变换方法：
$\hspace{23pt}\bullet\,$ 对于密码中的小写字母，参考九键手机键盘，将它们映射为对应的数字，具体地， $\mathtt{abc}$ 对应数字 $2$ 、 $\mathtt{def}$ 对应数字 $3$ 、 $\mathtt{ghi}$ 对应数字 $4$ 、 $\mathtt{jkl}$ 对应数字 $5$ 、 $\mathtt{mno}$ 对应数字 $6$ 、 $\mathtt{pqrs}$ 对应数字 $7$ 、 $\mathtt{tuv}$ 对应数字 $8$ 、 $\mathtt{wxyz}$ 对应数字 $9$ ；
$\hspace{23pt}\bullet\,$ 对于密码中的大写字母，先将其转换为小写，然后向后移动一位，即 $\mathtt{Z}$ 转换为 $\mathtt{a}$ ， $\mathtt{A}$ 转换为 $\mathtt{b}$ ， $\mathtt{B}$ 转换为 $\mathtt{c}$ ， $\cdots$ ， $\mathtt{Y}$ 转换为 $\mathtt{z}$ ， $\mathtt{Z}$ 转换为 $\mathtt{a}$ 。
$\hspace{23pt}\bullet\,$ 对于密码中的数字，保持不变。

$\hspace{15pt}$ 现在，请你将给定的密码按照上述规则进行变换。

输入描述:

在一行上输入一个长度为  的字符串  ，代表给定的密码。

输出描述:

在一行上输出一个字符串，代表变换后的密码。

示例1

输入

NowCoder123

输出

o69d6337123

算法知识视频讲解

qw2918

#include<iostream>
#include<string>
using namespace std;
const string dict1="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
const string dict2="bcdefghijklmnopqrstuvwxyza22233344455566677778889999";

char Char_Change(char a){
    for(int i=0;i<dict1.size();i++)
        if(dict1[i]==a) return dict2[i];
    return a;
}

int main(){
    //string data="YUANzhi1987";
    string data;
    while(getline(cin,data)){
    	for(int i=0;i<data.size();i++)
        	data[i] = Char_Change(data[i]);
    	cout<<data<<endl;
    }
    return 0;
}

发表于 2016-08-01 21:23:25 回复(86)

C++

矫健的鸽子

#include<iostream>
#include<string>
using namespace std;

//小写字母变换为九键键盘数字
char charToInt(const char& ch){
    if('a'<=ch&&ch<='c') return '2';
    else if('d'<=ch&&ch<='f') return '3';
    else if('g'<=ch&&ch<='i') return '4';
    else if('j'<=ch&&ch<='l') return '5';
    else if('m'<=ch&&ch<='o') return '6';
    else if('p'<=ch&&ch<='s') return '7';
    else if('t'<=ch&&ch<='v') return '8';
    else  return '9';
}
//大写字母变为小写字母后往后移位
char charMove(const char& ch){
    if(ch=='Z') return 'a';
    else return tolower(ch)+1;
}
int main(){
    string str;
    while(getline(cin,str)){
        string outStr;
        for(auto ch:str){
            if('a'<=ch&&ch<='z') outStr.push_back(charToInt(ch));
            else if('A'<=ch&&ch<='Z') outStr.push_back(charMove(ch));
            else outStr.push_back(ch);
        }
        cout<<outStr<<endl;
    }
    
}

发表于 2022-08-04 10:26:25 回复(0)

Python 3

牛客839922575号

string = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"
string2 = "bcdefghijklmnopqrstuvwxyza222333444555666777788899990123456789"
s = input()
for i in s:
print(string2[string.index(i)],end='')

发表于 2022-07-24 21:46:33 回复(0)

Python 3

来个offer叭！

def str_tran(get_str):
    lst_str = []
    for i in get_str:
        lst_str.append(i)
    for j in range(len(lst_str)):
        if ord(lst_str[j]) == ord('Z'):
            lst_str[j] = 'a'
        elif ord(lst_str[j]) >= 65 and ord(lst_str[j]) < 90:
            lst_str[j] = chr(ord(lst_str[j])+32+1)
        elif lst_str[j] in 'abc':
            lst_str[j] = '2'
        elif lst_str[j] in 'def':
            lst_str[j] = '3'
        elif lst_str[j] in 'ghi':
            lst_str[j] = '4'
        elif lst_str[j] in 'jkl':
            lst_str[j] = '5'
        elif lst_str[j] in 'mno':
            lst_str[j] = '6'
        elif lst_str[j] in 'pqrs':
            lst_str[j] = '7'
        elif lst_str[j] in 'tuv':
            lst_str[j] = '8'
        elif lst_str[j] in 'wxyz':
            lst_str[j] = '9'
    return ''.join(lst_str)
get_str = input()
print(str_tran(get_str))

发表于 2022-07-20 22:42:39 回复(0)

Java

spaceobj

import java.util.*;
public class Main{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
String[] str = sc.nextLine().split("");
String result = "";
for(int i=0;i<str.length;i++){
if("abc".contains(str[i])){
result = result+"2";
}else if("def".contains(str[i])){
result = result+"3";
}else if("ghi".contains(str[i])){
result = result+"4";
}else if("jkl".contains(str[i])){
result = result+"5";
}else if("mno".contains(str[i])){
result = result+"6";
}else if("pqrs".contains(str[i])){
result = result+"7";
}else if("tuv".contains(str[i])){
result = result+"8";
}else if("wxyz".contains(str[i])){
result = result+"9";
}else{
if("0123456789".contains(str[i])){
result = result+str[i];
}else{
char[] num = str[i].toCharArray();
if(num[0]==90){
char ch = (char) (97);
result = result+ch;
}else{
char ch = (char) (num[0] + 33);
result = result+ch;
}
}
}
}
System.out.println(result);
}
}

发表于 2022-05-24 15:04:14 回复(0)

Java

uniClover

import java.util.*;
public class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        char c[] = str.toCharArray();
        for(int i = 0; i<str.length() ; i++){
            if(c[i]>='A'&&c[i]<='Z'){
                if(c[i]+32 != 'z')
                    c[i] += 33;
                else
                    c[i] = 'a';
            }
            else if(c[i]=='a'||c[i]=='b'||c[i]=='c')
                c[i]='2';
            else if(c[i]=='d'||c[i]=='e'||c[i]=='f')
                c[i]='3';
            else if(c[i]=='g'||c[i]=='h'||c[i]=='i')
                c[i]='4';
            else if(c[i]=='j'||c[i]=='k'||c[i]=='l')
                c[i]='5';
            else if(c[i]=='m'||c[i]=='n'||c[i]=='o')
                c[i]='6';
            else if(c[i]=='p'||c[i]=='q'||c[i]=='r'||c[i]=='s')
                c[i]='7';
            else if(c[i]=='t'||c[i]=='u'||c[i]=='v')
                c[i]='8';
            else if(c[i]=='w'||c[i]=='x'||c[i]=='y'||c[i]=='z')
                c[i]='9';
            System.out.print(c[i]);
        }
        System.out.println();
    }
}

发表于 2022-03-22 15:15:21 回复(0)

Python3

牛客84500154号

str1 = input()
list1 = ['abc','def','ghi','jkl','mno','pqrs','tuv','wxyz']
for i in str1:
if i.islower():
for a in list1:
if i in a:
n=list1.index(a)+2
print(n,end='')
elif i.isupper():
print(chr(ord(i.lower())+1),end='')
else:
print(i,end='')

发表于 2022-01-19 23:22:58 回复(0)

viod

俺太笨了，只会枚举：

#include<stdio.h>
int main(){
    char c;
    while(~scanf("%c",&c)){
        if(c=='Z')
            printf("a");
        else if('A'<=c&&c<'Z')
            printf("%c",c+33);
        else if('a'<=c&&c<='z')
        {
            if('a'<=c&&c<='c') printf("2");
            if('d'<=c&&c<='f') printf("3");
            if('g'<=c&&c<='i') printf("4");
            if('j'<=c&&c<='l') printf("5");
            if('m'<=c&&c<='o') printf("6");
            if('p'<=c&&c<='s') printf("7");
            if('t'<=c&&c<='v') printf("8");
            if('w'<=c&&c<='z') printf("9");
        }
        else printf("%c",c);
    } printf("\n");
}

发表于 2021-12-28 22:05:35 回复(0)

Python3

Hyperpogger

number = {"2":"abc", "3":"def", "4":"ghi", "5":"jkl", "6":"mno", "7":"pqrs", "8":"tuv", "9":"wxyz"}
pw = list(input())
for i in range(len(pw)):
  if pw[i].islower():
    for key, value in number.items():
      if pw[i] in value:
        pw[i] = key
        break
  elif pw[i].isupper():
    if pw[i] == "Z":
      pw[i] = "a"
    else:
      pw[i] = chr(ord(pw[i].lower()) + 1)
print(*pw, sep="")

发表于 2021-11-04 03:42:40 回复(0)

Python 3

牛客952747261号

a="abcdefghijklmnopqrstuvwxyza"
w=input().strip()
p=""
for i in w:
    if i.islower():
        if i in "abc":
            p+="2"
        elif i in "def":
            p+="3"
        elif i in "ghi":
            p+="4"
        elif i in "jkl":
            p+="5"
        elif i in "mno":
            p+="6"
        elif i in "pqrs":
            p+="7"
        elif i in "tuv":
            p+="8"
        elif i in "wxyz":
            p+="9"
        else:
            pass
    elif i.isupper():
        inx=a.index(i.lower(),0,26)
        p+=a[inx+1]
    else:
        p+=i
print(p)

发表于 2021-09-16 02:27:22 回复(0)

Java

牛客最小的小白

import java.util.Scanner;

public class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        while(sc.hasNext()){
            String s = sc.nextLine();
            StringBuilder sb = new StringBuilder();
            for(int i=0; i<s.length(); i++){
                sb.append(get(s.charAt(i)));
            }
            System.out.println(sb.toString());
        }
    }
    
    private static char get(char c){
        if(c>='A' && c<='Z'){//大写字母，变小写后移一位
            if(c=='Z') return 'a';
            return (char)(c+1+('a'-'A'));
        }else if(c>='a' && c<='z'){//小写字母
//             switch(c){
//                 case 'a':case'b':case'c': return '2';
//                 case 'd':case'e':case'f': return '3';
//                 case 'g':case'h':case'i': return '4';
//                 case 'j':case'k':case'l': return '5';
//                 case 'm':case'n':case'o': return '6';
//                 case 'p':case'q':case'r':case's': return '7';
//                 case 't':case'u':case'v': return '8';
//                 case 'w':case'x':case'y':case 'z': return '9';
//                 default: return ' ';
//             }
            String s = String.valueOf(c);
            if("abc".contains(s)) return '2';
            if("def".contains(s)) return '3';
            if("ghi".contains(s)) return '4';
            if("jkl".contains(s)) return '5';
            if("mno".contains(s)) return '6';
            if("pqrs".contains(s)) return '7';
            if("tuv".contains(s)) return '8';
            if("wxyz".contains(s)) return '9';
            return ' ';
        }else{//其他
            return c;
        }
    }
}

发表于 2021-08-03 15:08:08 回复(0)

Java

CaesarZ99

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Decrypt {
    public static final Map<Integer, String> MAP = new HashMap<>();

    static {
        MAP.put(2, "abc");
        MAP.put(3, "def");
        MAP.put(4, "ghi");
        MAP.put(5, "jkl");
        MAP.put(6, "mno");
        MAP.put(7, "pqrs");
        MAP.put(8, "tuv");
        MAP.put(9, "wxyz");
    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        char[] pwds = sc.next().toCharArray();
        String decyptedPwd = "";
        int step = 32;
        for (Character pwd : pwds) {
            //大写字母范围
            if (pwd >= 65 && pwd <= 90) {
                if (pwd + step == 122) {
                    decyptedPwd += "a";
                } else {
                    decyptedPwd += (char) ((pwd + step) + 1);
                }
            }else {
                for (Map.Entry<Integer, String> map : MAP.entrySet()) {
                    if (map.getValue().contains(String.valueOf(pwd))) {
                        decyptedPwd += map.getKey();
                    }
                }
                if (!(pwd >= 97 && pwd <= 122)){
                    decyptedPwd+=pwd;
                }
            }
        }
        System.out.println(decyptedPwd);
    }
}

发表于 2021-07-15 17:17:20 回复(0)

pein531

初始化一个九键映射表，然后依照题意按条件进行转化即可

mp = dict()
mp['0'] = '0'
mp['1'] = '1'
mp['a'] = '2'
mp['b'] = '2'
mp['c'] = '2'
mp['d'] = '3'
mp['e'] = '3'
mp['f'] = '3'
mp['g'] = '4'
mp['h'] = '4'
mp['i'] = '4'
mp['j'] = '5'
mp['k'] = '5'
mp['l'] = '5'
mp['m'] = '6'
mp['n'] = '6'
mp['o'] = '6'
mp['p'] = '7'
mp['q'] = '7'
mp['r'] = '7'
mp['s'] = '7'
mp['t'] = '8'
mp['u'] = '8'
mp['v'] = '8'
mp['w'] = '9'
mp['x'] = '9'
mp['y'] = '9'
mp['z'] = '9'

while True:
    try:
        trans = input().strip()
        res = []
        for i in range(len(trans)):
            s = trans[i]
            ascII = ord(s)
            if ascII >= 65 and ascII <= 90:
                if s == 'Z':
                    res.append('a')
                else:
                    res.append(chr(ascII + 33))
            elif ascII >= 97 and ascII <= 122:
                res.append(mp[s])
            else:
                res.append(s)
        print(''.join(res))
    except:
        break

发表于 2021-03-20 16:34:46 回复(0)

国际精神病研究院王医生

//穷举法 时间复杂度 0(n)
import java.util.*;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    //大写变成n+1的小写， 小写变为数字，数字还是数字
    public static String value = "bcdefghijklmnopqrstuvwxyza222333444555666777788899990123456789";
    public static String key = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
    public static void main(String[] args) {
//          System.out.println(key.length()+"-"+value.length());
        Map<String,String> map = new HashMap();
          for(int i = 0; i<key.length(); i++){
             map.put(key.charAt(i)+"",value.charAt(i)+""); 
            }
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        StringBuffer sb = new StringBuffer();
        while (in.hasNext()) { // 注意 while 处理多个 case
            String a = in.next();
            for(int i = 0; i<a.length(); i++){
               sb.append(map.get(a.charAt(i)+""));
            }
            System.out.println(sb);
        }
    }
}

编辑于 2021-02-28 12:41:56 回复(0)

C/C++

啊啦啊啊啊k

最笨，最不优美的方法

#include<iostream>
#include <string>
using namespace std;

int main() {
    string str;
    while(cin >> str){
        int len = str.size();
        for(int i = 0; i<len ;i++){
            if(str[i]>='A' && str[i]<'Z'){
                str[i] = str[i] + 33;
                continue; // continue必须加，否则后面继续转码
            }
            if(str[i] == 'Z'){
                str[i] = 'a';
                continue;
            }
            
            if(str[i]>='a' && str[i]<='c')
                str[i] = '2';
            if(str[i]>='d' && str[i]<='f')
                str[i] = '3';
            if(str[i]>='g' && str[i]<='i')
                str[i] = '4';
            if(str[i]>='j' && str[i]<='l')
                str[i] = '5';
            if(str[i]>='m' && str[i]<='o')
                str[i] = '6';
            if(str[i]>='p' && str[i]<='s')
                str[i] = '7';
            if(str[i]>='t' && str[i]<='v')
                str[i] = '8';
            if(str[i]>='w' && str[i]<='z')
                str[i] = '9';
        }
        cout << str<< endl;
    }
    return 0;
}

发表于 2021-01-22 21:21:35 回复(0)

Python

大溪地渔民

import sys


a = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"
b = "bcdefghijklmnopqrstuvwxyza222333444555666777788899990123456789"
output = ""

for s in sys.stdin:
    s = s.strip()
    for c in s:
        output += b[a.index(c)]
        
print(output)

发表于 2020-12-14 20:17:21 回复(0)

Java

305602188

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while(sc.hasNext()){
            String string = sc.nextLine();
            
            char[] chs = string.toCharArray();
            String res = "";
            for (int i = 0; i < chs.length ; i++) {
                if(chs[i]>='a' && chs[i]<='z'){
                    res+=lowCase2digital(chs[i]);//小写变数字
                }else if(chs[i]>='A' && chs[i]<='Z'){
                    res += UpCase2lowCase(chs[i]);
                }else{
                    res += chs[i];
                }
            }
            System.out.println(res);
        }
    }
    public static char UpCase2lowCase(char c){
        char tmp = (char) (c ^ ' ');
        return (char)('a'+(tmp - 'a' + 1)%26);
        
    }
    public static char lowCase2digital(char c){
        if(c>='a' && c<= 'c'){
            return '2';
        }else if(c>='d' && c<= 'f'){
            return '3';
        }else if(c>='g' && c<= 'i'){
            return '4';
        }else if(c>='j' && c<= 'l'){
            return '5';
        }else if(c>='m' && c<= 'o'){
            return '6';
        }else if(c>='p' && c<= 's'){
            return '7';
        }else if(c>='t' && c<= 'v'){
            return '8';
        }else{
            return '9';
        }
    }
}

发表于 2020-08-22 14:45:03 回复(0)

C/C++

牛客464555119号

#include <bits/stdc++.h>
using namespace std;
int main(){
    string a;
    string b[8]={"abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"};
    while(cin>>a){
        for(int i=0;i<a.size();i++){
            if(a[i]>='A'&&a[i]<='Z')
                if(a[i]=='Z')
                    a[i]='a';
                else
                    a[i]=tolower(a[i])+1;
            else if(a[i]>='a'&&a[i]<='z'){
                for(int j=0;j<8;j++){
                    if(b[j].find(a[i])!=b[j].npos)
                        a[i]=j+'2';
                }
            }
        }
        cout<<a<<endl;
    }
    return 0;
}

发表于 2020-08-16 16:49:30 回复(0)

Java

丛林守望者

import java.util.*;
public class Main{
    public static void main(String[] args) {
        Map<String, String>  map = new HashMap<>();
        map.put("abc", "2");
        map.put("def", "3");
        map.put("ghi", "4");
        map.put("jkl", "5");
        map.put("mno", "6");
        map.put("pqrs", "7");
        map.put("tuv", "8");
        map.put("wxyz", "9");
        Scanner scanner = new Scanner(System.in);
        while (scanner.hasNext()) {
            String line = scanner.nextLine();
            char[] charArr = line.toCharArray();
            StringBuilder stringBuilder = new StringBuilder();
            for (char ch : charArr) {
                if (ch >= 'A' && ch <= 'Y') {
                    String ss = String.valueOf((char) (ch + 1)).toLowerCase();
                    stringBuilder.append(ss);
                } else if (ch == 'Z') {
                    stringBuilder.append('a');
                } else if (ch >= 'a' && ch <= 'z') {
                    map.forEach((key, value) -> {
                        if (key.contains(String.valueOf(ch))) {
                            String ss = map.get(key);
                            stringBuilder.append(ss);
                        }
                    });
                } else {
                    stringBuilder.append(ch);
                }
            }
            System.out.println(stringBuilder.toString());
        }
    }
}

编辑于 2020-08-09 13:28:12 回复(1)

她说她是傻子

对不起，我太菜了，只能想到这种傻方法。真羡慕大佬们

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while(sc.hasNext()){
            String s = sc.nextLine();
            StringBuffer stringBuffer = new StringBuffer();
            for (int i = 0; i < s.length(); i++) {
                if (s.charAt(i) >= 'A' && s.charAt(i) <= 'Z'){
                    String el = String.valueOf(s.charAt(i));
                    String s1 = el.toLowerCase();
                    char content;
                    if (s1.charAt(0) == 'z'){
                        content = 'a';
                    }else{
                        content = (char) (s1.charAt(0)+1);
                    }
                    stringBuffer.append(content);
                }else if (s.charAt(i) >= 'a' && s.charAt(i) <= 'z'){
                    int content = 0;
                    char lower = s.charAt(i);
                    if (lower>= 'a' && lower <= 'c'){
                        content = 2;
                    }
                    if (lower>= 'd' && lower <= 'f'){
                        content = 3;
                    }
                    if (lower>= 'g' && lower <= 'i'){
                        content = 4;
                    }
                    if (lower>= 'j' && lower <= 'l'){
                        content = 5;
                    }
                    if (lower>= 'm' && lower <= 'o'){
                        content = 6;
                    }
                    if (lower>= 'p' && lower <= 's'){
                        content = 7;
                    }
                    if (lower>= 't' && lower <= 'v'){
                        content = 8;
                    }
                    if (lower>= 'w' && lower <= 'z'){
                        content = 9;
                    }
                    stringBuffer.append(content);
                }else {
                    stringBuffer.append(s.charAt(i));
                }
            }
            System.out.println(stringBuffer.toString());
        }
    }
}

发表于 2020-07-10 12:21:40 回复(0)