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简单密码

[编程题]简单密码

热度指数：307197 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 32M，其他语言64M
算法知识视频讲解

$\hspace{15pt}$ 规定这样一种密码的变换方法：
$\hspace{23pt}\bullet\,$ 对于密码中的小写字母，参考九键手机键盘，将它们映射为对应的数字，具体地， $\mathtt{abc}$ 对应数字 $2$ 、 $\mathtt{def}$ 对应数字 $3$ 、 $\mathtt{ghi}$ 对应数字 $4$ 、 $\mathtt{jkl}$ 对应数字 $5$ 、 $\mathtt{mno}$ 对应数字 $6$ 、 $\mathtt{pqrs}$ 对应数字 $7$ 、 $\mathtt{tuv}$ 对应数字 $8$ 、 $\mathtt{wxyz}$ 对应数字 $9$ ；
$\hspace{23pt}\bullet\,$ 对于密码中的大写字母，先将其转换为小写，然后向后移动一位，即 $\mathtt{Z}$ 转换为 $\mathtt{a}$ ， $\mathtt{A}$ 转换为 $\mathtt{b}$ ， $\mathtt{B}$ 转换为 $\mathtt{c}$ ， $\cdots$ ， $\mathtt{Y}$ 转换为 $\mathtt{z}$ ， $\mathtt{Z}$ 转换为 $\mathtt{a}$ 。
$\hspace{23pt}\bullet\,$ 对于密码中的数字，保持不变。

$\hspace{15pt}$ 现在，请你将给定的密码按照上述规则进行变换。

输入描述:

在一行上输入一个长度为  的字符串  ，代表给定的密码。

输出描述:

在一行上输出一个字符串，代表变换后的密码。

示例1

输入

NowCoder123

输出

o69d6337123

算法知识视频讲解

Python 3

没有吃饱

keypad_mapping = {

"a": "2",

"b": "2",

"c": "2",

"d": "3",

"e": "3",

"f": "3",

"g": "4",

"h": "4",

"i": "4",

"j": "5",

"k": "5",

"l": "5",

"m": "6",

"n": "6",

"o": "6",

"p": "7",

"q": "7",

"r": "7",

"s": "7",

"t": "8",

"u": "8",

"v": "8",

"w": "9",

"x": "9",

"y": "9",

"z": "9",

}

def change_password(passwd):

list = []

for i in passwd:

if i.isupper():

if i == "Z":

list.append("a")

else:

list.append(chr(ord(i.lower()) + 1))

elif i.islower():

list.append(keypad_mapping[i])

else:

list.append(i)

return list

password = input()

print(*change_password(password), sep="")

发表于 2024-11-29 20:58:49 回复(0)

Python 3

一个非让他

#小写字母处理

def islowers(i:str):

if i == 'a' or i == 'b' or i == 'c':

return '2'

elif i == 'd' or i == 'e' or i == 'f':

return '3'

elif i == 'g' or i == 'h' or i == 'i':

return '4'

elif i == 'j' or i == 'k' or i == 'l':

return '5'

elif i == 'm' or i == 'n' or i == 'o':

return '6'

elif i == 'p' or i == 'q' or i == 'r' or i == 's':

return '7'

elif i == 't' or i == 'u' or i == 'v':

return '8'

else:

return '9'

#大写字母处理

def isuuper(s):

if s == 'Z':

return 'a'

else:

t = s.lower()

return chr(ord(t)+1)

#对输入的字符串进行转换

stri = input()

re_sting =''

for i in stri:

if i.islower():

re_sting += islowers(i)

elif i.isupper():

re_sting += isuuper(i)

else:

re_sting += i

print(re_sting)

发表于 2024-08-09 00:09:33 回复(0)

Python 3

Lion_gwin

word = input()

new_word = ''

for i in word:

if i.isdigit():

new_word = new_word + i

elif i.isalpha() and i.isupper():

if i == 'Z':

new_word = new_word + 'a'

else:

i = chr(ord(i.lower())+1)

new_word = new_word + i

elif i == 'a' or i == 'b' or i == 'c':

new_word = new_word + '2'

elif i == 'd' or i == 'e' or i == 'f':

new_word = new_word + '3'

elif i == 'g' or i == 'h' or i == 'i':

new_word = new_word + '4'

elif i == 'j' or i == 'k' or i == 'l':

new_word = new_word + '5'

elif i == 'm' or i == 'n' or i == 'o':

new_word = new_word + '6'

elif i == 'p' or i == 'q' or i == 'r' or i == 's':

new_word = new_word + '7'

elif i == 't' or i == 'u' or i == 'v':

new_word = new_word + '8'

elif i == 'w' or i == 'x' or i == 'y' or i == 'z':

new_word = new_word + '9'

elif i == '1':

new_word = new_word + '1'

elif i == '0':

new_word = new_word + '0'

print(new_word)

编辑于 2024-04-01 21:13:38 回复(0)

Python 3

牛客399544825号

while True:

try:

A='abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'

B='22233344455566677778889999bcdefghijklmnopqrstuvwxyza'

list1=[]

list2=[]

#将A,B写入列表list1和list2 中

for i in A:

list1.append(i)

for j in B:

list2.append(j)

res=input()

ans=[]

for i in res:

if i in list1:

ans.append(list2[list1.index(i)])

else:

ans.append(i)

print(''.join(ans))

except:

break

#第二种比较合适的方法：

while True:

try:

pw=input()

res=[]

for i in pw:

if i.isupper() and i!='Z':

res.append(chr(ord(i.lower())+1))

if i=='Z':

res.append('a')

elif ord(i) in range(97,123):

if i in 'abc':

res.append('2')

if i in 'def':

res.append('3')

if i in 'ghi':

res.append('4')

if i in 'jkl':

res.append('5')

if i in 'mno':

res.append('6')

if i in 'pqrs':

res.append('7')

if i in 'tuv':

res.append('8')

if i in 'wxyz':

res.append('9')

else:

res.append(i)

print(''.join(res))

except:

break

发表于 2024-03-04 15:01:15 回复(0)

Python 3

Laydia

import sys

mima = {'abc': 2, 'def': 3, 'ghi': 4, 'jkl': 5, 'mno': 6, 'pqrs': 7, 'tuv': 8, 'wxyz': 9}
translated_mima = ''

for line in sys.stdin:
    a = line.split()
    for s in a[0]:
        if s.islower() == True:
            for keys in mima.keys():
                if s in keys:
                    translated_mima = translated_mima + str(mima[keys])
        elif s.isupper() == True:
            if s != 'Z':
                s = chr(ord(s) + 33)
            else:
                s = 'a' 
            translated_mima = translated_mima + s
        else:
            translated_mima = translated_mima + s

print(translated_mima)

发表于 2023-03-23 21:59:51 回复(0)

Python 3

恶作剧之神阿蒙

str1 = input()

str2 = ""

lis = ["abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"]

for i in str1:

if 65 <= ord(i) <= 90:

if ord(i)==90:

str2 += chr(ord(i) + 7)

else:

str2 += chr(ord(i) + 33)

elif 97 <= ord(i) <= 122:

for j in lis:

if i in j:

str2 += str(lis.index(j) + 2)

break

else:

str2 += i

print(str2)

发表于 2023-02-20 16:56:24 回复(0)

Python 3

牛哼哼

#encoding=utf-8

str1 = input()
dict1 = {"1":1,"abc":2,"def":3,"ghi":4,"jkl":5,"mno":6,"pqrs":7,"tuv":8,"wxyz":9,"0":0}
list1 = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]

en = []
num = []
new = ""
for key,values in dict1.items():
en.append(key)
num.append(values)
for i in str1:
if i.isalpha():
if i.isupper():
x = list1.index(i.lower())#当是大写时，获取字母的下标
if x+1 == len(list1):
x = -1
new= new+list1[x+1] #将字母的后一个添加到列表
else:
for n in en:
if i in n:
x = en.index(n)
new = new+str(num[x])
else:
new = new+i
print(new)

发表于 2022-11-04 09:25:55 回复(0)

Python 3

四季四季四季

password = input()
New_pass = ''
beta = 'abc def ghi jkl mno pqrs tuv wxyz'
for alp in password:
    if alp.isalpha():
        if alp.isupper() and alp != 'Z':
            New_pass += str(chr(ord(alp.lower()) + 1))
        elif alp == 'Z':
            New_pass += 'a'
        elif alp.islower():
            for i,j in enumerate(beta.split()):
                if alp in j:
                    New_pass += str(i + 2)
    else:
        New_pass += alp
print(New_pass)

发表于 2022-08-30 11:33:38 回复(0)

Python 3

牛客428544446号

s=input()
res=[]
for i in s:
if i.isdigit(): #数字
res.append(i)
elif i.isupper() and i != 'Z': #大写
res.append(chr(ord(i.lower()) + 1)) #lower()转为小写，ord()转为十进制，chr()转为ASCII字符
elif i == 'Z':
res.append('a')
else:
if i in 'abc':
res.append('2')
elif i in 'def':
res.append('3')
elif i in 'ghi':
res.append('4')
elif i in 'jkl':
res.append('5')
elif i in 'mno':
res.append('6')
elif i in 'pqrs':
res.append('7')
elif i in 'tuv':
res.append('8')
else:
res.append('9')
print(''.join(res))

发表于 2022-08-27 22:09:50 回复(0)

Python 3

牛客875760860号

简单思路，先创建一个dict用来存储这些转化

大写的转化那里需要用到ASC2码的转化

大写先用str.lower()转小写

然后用ord转ASC码

如果是z的话，需要手动定义等于z

其他的子需要将asc码+1就得到了下一个字母的asc码

import sys
 
for line in sys.stdin:
    a = line.split()
    str_input = a[0]


change_dict = {"1":1,"a":2,"b":2,"c":2,"d":3,"e":3,"f":3,"g":4,"h":4,"i":4,
              "j":5,"k":5,"l":5,"m":6,"n":6,"o":6,"p":7,"q":7,"r":7,"s":7,
              "t":8,"u":8,"v":8,"w":9,"x":9,"y":9,"z":9,"0":0}
result = ""
for i in str_input:
    if(i.isupper()):
        #先转化小写
        up_i = i.lower()

        #转化码
        ac2_up_i = ord(up_i)
        if(ac2_up_i == ord("z")):
            ac2_up_i = ord("a")
            result = result + chr(ac2_up_i)
        else:
            result = result + chr(ac2_up_i+1)
    elif(i.isdigit()):
        result = result + str(i)
    else:
        result = result + str(change_dict[i])
print(result)

发表于 2022-08-18 14:47:26 回复(0)

Python 3

牛客143151496号

# 输入一串字符
str1 = list(input())  # 输入的转化为列表
# 注意这里不能直接把输入的进行切分成列表
# str1 = input().strip()#这样是错误的写法
# 定义一个用于存储变量的
temp = ''
# 遍历列表
for i in str1:
    # 分成三种情况：小写，大写，数字
    # 首先解决是小写子母的
    if i.islower():  # 小写
        abc_list = ["a","b","c"]
        def_list = ["d","e","f"]
        ghi_list = ["g","h","i"]
        jkl_list = ["j","k","l"]
        mon_list = ["m","o","n"]
        pqrs_list = ["p","q","r","s"]
        tuv_list = ["t","u","v"]
        wxyz_list = ["w","x","y","z"]

        if i in abc_list:
            i = "2"
            temp = temp + i
        elif i in def_list:
            i = "3"
            temp = temp + i
        elif i in ghi_list:
            i = "4"
            temp = temp + i
        elif i in jkl_list:
            i = "5"
            temp = temp + i
        elif i in mon_list:
            i = "6"
            temp = temp + i
        elif i in pqrs_list:
            i = "7"
            temp = temp + i
        elif i in tuv_list:
            i = "8"
            temp = temp + i
        elif i in wxyz_list:
            i = "9"
            temp = temp + i

    # elif a.isnumeric():
    # 大写：
    elif i.isupper(): # 大写
        # 把大写的转化成小写字母
        i =  i.lower()
        # 使用ascall码进行加一转化
        i_ascall = ord(i) + 1
        # 如果是123的ascall码那么要把它变成a的,也就是对应z的ascall码+1
        if i_ascall == 123:
            i_ascall = ord("a")
        i = chr(i_ascall)  # 在把ascall码转换回字母完成转化
        temp = temp + i
    # 如果是数字，那么可以直接使用
    elif i.isalnum(): # 数字
        i = str(i)  # 把数字转化成字符串，否则无法拼接
        temp = temp + i

print(temp)

发表于 2022-08-17 23:19:09 回复(0)

Python 3

梭梭72588922号

def encryption(string):
    dct = {}
    key   = 'ZABCDEFGHIJKLMNOPQRSTUVWXYabcdefghijklmnopqrstuvwxyz1234567890'
    value = 'abcdefghijklmnopqrstuvwxyz222333444555666777788899991234567890'
    for i,s in enumerate(key):
        k, v = s, value[i]
        dct[k] = v
    for i in string:
        print(dct[i], end='')
encryption(input())

发表于 2022-08-13 18:34:40 回复(0)

Python 3

牛客262501032号

password_0 = input()
pas=[]
for i in password_0:
    if i in 'abc':
        pas.append('2')
    elif i in 'def':
        pas.append('3')
    elif i in 'ghi':
        pas.append('4')
    elif i in 'jkl':
        pas.append('5')
    elif i in 'mno':
        pas.append('6')
    elif i in 'pqrs':
        pas.append('7')
    elif i in 'tuv':
        pas.append('8')
    elif i in 'wxyz':
        pas.append('9')
    elif i.isupper() and i != 'Z':
        pas.append(chr(ord(i.lower())+1))
    elif i=='Z':
        pas.append('a')
    else:   #i.isdigit()判断为数字，此处else包含数字和其他字符
        pas.append(i)
print(''.join(pas))

发表于 2022-08-02 23:18:07 回复(0)

Python 3

牛客570647112号

ip = input()
for c in ip:
if "a"<=c<="z": # 小写
if 'a'<=c<='c':
print(2,end='')
elif 'd'<=c<='f':
print(3,end='')
elif 'g'<=c<='i':
print(4,end='')
elif 'j'<=c<='l':
print(5,end='')
elif 'm'<=c<='o':
print(6,end='')
elif 'p'<=c<='s':
print(7,end='')
elif 't'<=c<='v':
print(8,end='')
elif '9'<=c<='z':
print(9,end='')

elif "A"<=c<="Z":
tmp = c.lower() # 大写变小写
tmp = ord(tmp) + 1 # 往前走1
if tmp > ord('z'):
print('a', end='')
else:
print(chr(tmp), end='')
pass #大写
else:
print(c,end='')

发表于 2022-07-28 20:09:08 回复(0)

Python 3

牛客839922575号

string = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"
string2 = "bcdefghijklmnopqrstuvwxyza222333444555666777788899990123456789"
s = input()
for i in s:
print(string2[string.index(i)],end='')

发表于 2022-07-24 21:46:33 回复(0)

Python 3

649924619

s = input()
a = []
zhimu = "abcdefghijklmnopqrstuvwxyz"
for i in range(len(s)):
    a.append(s[i])
    if a[i] in 'abc':
        a[i] = 2
    elif a[i] in 'def':
        a[i] = 3
    elif a[i] in 'ghi':
        a[i] = 4
    elif a[i] in 'jkl':
        a[i] = 5
    elif a[i] in 'mno':
        a[i] = 6
    elif a[i] in 'pqrs':
        a[i] = 7
    elif a[i] in 'tuv':
        a[i] = 8
    elif a[i] in 'wxyz':
        a[i] = 9
    elif a[i].isupper():
        if a[i] !='Z':
            b = a[i].lower()
            indec = zhimu.index(b)
#             print(indec)
            a[i] = zhimu[indec+1]
#             print(a[i])
        if a[i] == 'Z':
            a[i] = 'a'
    else:
        a[i] = a[i]
# print(a)
pp = ''
for i in a:
    pp = pp+str(i)
print(pp)

发表于 2022-07-23 15:43:38 回复(0)

Python 3

来个offer叭！

def str_tran(get_str):
    lst_str = []
    for i in get_str:
        lst_str.append(i)
    for j in range(len(lst_str)):
        if ord(lst_str[j]) == ord('Z'):
            lst_str[j] = 'a'
        elif ord(lst_str[j]) >= 65 and ord(lst_str[j]) < 90:
            lst_str[j] = chr(ord(lst_str[j])+32+1)
        elif lst_str[j] in 'abc':
            lst_str[j] = '2'
        elif lst_str[j] in 'def':
            lst_str[j] = '3'
        elif lst_str[j] in 'ghi':
            lst_str[j] = '4'
        elif lst_str[j] in 'jkl':
            lst_str[j] = '5'
        elif lst_str[j] in 'mno':
            lst_str[j] = '6'
        elif lst_str[j] in 'pqrs':
            lst_str[j] = '7'
        elif lst_str[j] in 'tuv':
            lst_str[j] = '8'
        elif lst_str[j] in 'wxyz':
            lst_str[j] = '9'
    return ''.join(lst_str)
get_str = input()
print(str_tran(get_str))

发表于 2022-07-20 22:42:39 回复(0)

Python 3

AlexLyn_00

python3 可以事先写个dict

while True:
    try:
        code_input = input()
        code_output = ""
        for element in code_input:
            if element.isdigit():
                code_output += element
            elif element.isalpha():
                if "A"<=element<"Z":
                    element = chr(ord(element.lower())+1)
                    code_output += element
                elif element == "Z":
                    code_output += "a"
                elif element in "abc":
                    code_output += "2"
                elif element in "def":
                    code_output += "3"
                elif element in "ghi":
                    code_output += "4"
                elif element in "jkl":
                    code_output += "5"
                elif element in "mno":
                    code_output += "6"
                elif element in "pqrs":
                    code_output += "7"
                elif element in "tuv":
                    code_output += "8"
                elif element in "wxyz":
                    code_output += "9"
        print(code_output)
        
    except:
        break

发表于 2022-07-13 16:56:41 回复(0)