根据输入的日期，计算是这一年的第几天。
保证年份为4位数且日期合法。
进阶：时间复杂度：%5C)
，空间复杂度：%5C)
[编程题]计算日期到天数转换
#include <stdio.h>
int main() {
int y, m, d, day = 0;
int date[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
scanf("%d%d%d", &y, &m, &d);
if (m <= 2) {
for (int i = 0; i < m - 1; i++)
day += date[i];
day += d;
printf("%d", day);
} else if (m > 2) {
for (int i = 0; i < m - 1; i++)
day += date[i];
day += d;
if ((y % 4 == 0 && y % 100 != 0) || (y % 400 == 0))
printf("%d", day + 1);
else
printf("%d", day);
}
return 0;
}
发表于 2024-08-22 21:24:17
回复(0)
#include <stdio.h>
int IsLeapYear(int year)
{
if((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
return 1;
else return 0;
}
int main() {
int month[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
int My_year;
scanf("%d",&My_year);
int My_month;
scanf("%d",&My_month);
int My_day;
scanf("%d",&My_day);
if(IsLeapYear(My_year)) month[1]++;
int sum = 0;
for(int i = 0;i < My_month - 1;i++)
{
sum += month[i];
}
sum += My_day;
printf("%d",sum);
return 0;
}
发表于 2024-07-02 23:03:18
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#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
int main() {
int a, b;
int year, month, day;
int sum = 0;
scanf("%d %d %d", &year, &month, &day);
int days[] = { 31,28,31,30,31,30,31,31,30,31,30,31 };//平年
int days2[] = { 31,29,31,30,31,30,31,31,30,31,30,31 };//闰年
for (int i = 1; i < month; i++)
{
if ((year % 400 == 0) || ((year % 100 != 0) && (year % 4 == 0)))
{
sum += days2[i - 1];
}
else
sum += days[i - 1];
}
printf("%d", sum + day);
return 0;
}
发表于 2024-04-24 23:30:46
回复(0)
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int calculate_day(int year, int mouth)
{
int days;
switch (mouth) {
case 1:
days = 31;
break;
case 2:
if (year % 400 == 0) {
days = 29;
} else if ((year % 4 == 0) && (year % 100 != 0)) {
days = 29;
} else{
days = 28;
}
break;
case 3:
days = 31;
break;
case 4:
days = 30;
break;
case 5:
days = 31;
break;
case 6:
days = 30;
break;
case 7:
days = 31;
break;
case 8:
days = 31;
break;
case 9:
days = 30;
break;
case 10:
days = 31;
break;
case 11:
days = 30;
break;
case 12:
days = 31;
break;
}
return days;
}
// 4年一润，闰年28天，平时29天，1 3 5 7 8 10 12 共31天，2 4 6 9 11 共30天
int main() {
int year;
int mouth;
int day;
int dates[12];
int maxday = 0;
while (scanf("%d %d %d", &year, &mouth, &day) != EOF) { // 注意 while 处理多个 case
// 64 位输出请用 printf("%lld") to
memset(dates, 0, sizeof(dates));
for (int i = 1; i <= 12; i++) {
dates[i - 1] = calculate_day(year, i);
// printf("%d ", dates[i - 1]);
}
// printf("\n");
for (int i = 1; i < mouth; i++) {
maxday += dates[i - 1];
}
maxday += day;
printf("%d\n", maxday);
}
return 0;
}
发表于 2024-04-09 22:23:36
回复(0)
#include <stdio.h>
int leapyear(int year)//判断是否为闰年
{
return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
}
int MonthDay(int year, int month, int day)//用数组存储每月的天数
{
int daysmonth[] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
//是闰年就修改二月的值
if (leapyear(year))
{
daysmonth[2] = 29;
}
int DayCount = day;//初始化天数为当前给定天数
for (int i = 1; i < month; ++i)//遍历每月的天数累加到给定天数上
{
DayCount += daysmonth[i];
}
return DayCount;
}
int main()
{
int year, month, day;
scanf("%d %d %d", &year, &month, &day);
int size = MonthDay(year, month, day);
printf("%d\n", size);
return 0;
}
发表于 2024-03-03 14:57:11
回复(0)
#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
int function(int year)
{
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
{
return 1;
}
else
{
return 0;
}
}
int main()
{
int year = 0;
int month = 0;
int day = 0;
int a = 0;
int num = 0;
scanf("%d %d %d", &year, &month, &day);
a=function(year);
if (a == 1)
{
switch (month)
{
case 12:num += 30;
case 11:num += 31;
case 10:num += 30;
case 9:num += 31;
case 8:num += 31;
case 7:num += 30;
case 6:num += 31;
case 5:num += 30;
case 4:num += 31;
case 3:num += 29;
case 2:num+=31;
}
printf("%d", num + day);
}
else
{
switch (month)
{
case 12:num += 30;
case 11:num += 31;
case 10:num += 30;
case 9:num += 31;
case 8:num += 31;
case 7:num += 30;
case 6:num += 31;
case 5:num += 30;
case 4:num += 31;
case 3:num += 28;
case 2:num += 31;
}
printf("%d", num + day);
}
return 0;
}
编辑于 2024-01-06 14:19:37
回复(1)
#include <stdio.h>
int isrun(int year)//润年规则，4润百不润，400也润
{
if(year%4==0 && year%100 !=0 || year%400 ==0)
return 1;
return 0;
}
int math(int arr[],int month)
{
int num =0;
for(int i =0;i<month-1;i++)
{
num +=arr[i];
}
return num;
}
int num_day(int year, int month ,int day)
{
int arr1[12]={31,28,31,30,31,30,31,31,30,31,30,31};//非润年天数
int num =0;
int flag = isrun(year);
if(flag)//如果是闰年
{
arr1[1] = 29;
num =math(arr1,month)+day;
}
else
{
num =math(arr1,month)+day;
}
return num;
}
int main()
{
int year = 0;
int month = 0;
int day =0;
scanf("%d %d %d",&year,&month,&day);
int ret = num_day(year,month,day);
printf("%d",ret);
return 0;
}
发表于 2023-12-10 18:21:52
回复(0)
#include <stdio.h>
int year(int n)
{
if((n%4==0&&n%100!=0)||n%400==0)
return 1;
return 0;
}
int main() {
int arr[3];
int day[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
for(int i = 0;i<3;i++)
{
scanf("%d",&arr[i]);
}
int ret = arr[2];
if(year(arr[0]))
{
day[1] = 29;
}
for(int i = 0;i<arr[1]-1;i++)
{
ret += day[i];
}
printf("%d\n",ret);
return 0;
}
发表于 2023-10-13 20:29:02
回复(0)
#include <stdio.h>
//暴力方法
int main()
{
int year;
int month;
int day;
scanf("%d %d %d",&year,&month,&day);
int sum =0;
//1 3 5 7 8 10 12 ——31天
//4 6 9 11 ——30天
//闰年2月 ——29天
//平年2月 ——28天
//如果year是闰年 2000 11 15
if((year%4==0&&year%100!=0)||(year%400==0))
{
switch(month)
{
case 1:
sum=day;
break;
case 2:
sum=31+day;
break;
case 3:
sum=31+29+day;
break;
case 4:
sum=31+29+31+day;
break;
case 5:
sum=31+29+31+30+day;
break;
case 6:
sum=31+29+31+30+31+day;
break;
case 7:
sum=31+29+31+30+31+30+day;
break;
case 8:
sum=31+29+31+30+31+30+31+day;
break;
case 9:
sum=31+29+31+30+31+30+31+31+day;
break;
case 10:
sum=31+29+31+30+31+30+31+31+30+day;
break;
case 11:
sum=31+29+31+30+31+30+31+31+30+31+day;
break;
case 12:
sum=31+29+31+30+31+30+31+31+30+31+30+day;
break;
}
}
else
{
switch(month)
{
case 1:
sum=day;
break;
case 2:
sum=31+day;
break;
case 3:
sum=31+28+day;
break;
case 4:
sum=31+28+31+day;
break;
case 5:
sum=31+28+31+30+day;
break;
case 6:
sum=31+28+31+30+31+day;
break;
case 7:
sum=31+28+31+30+31+30+day;
break;
case 8:
sum=31+28+31+30+31+30+31+day;
break;
case 9:
sum=31+28+31+30+31+30+31+31+day;
break;
case 10:
sum=31+28+31+30+31+30+31+31+30+day;
break;
case 11:
sum=31+28+31+30+31+30+31+31+30+31+day;
break;
case 12:
sum=31+28+31+30+31+30+31+31+30+31+30+day;
break;
}
}
printf("%d",sum);
return 0;
}
发表于 2023-08-16 18:55:36
回复(1)
#include <stdio.h>
int main()
{
int year,month,day;
scanf("%d %d %d",&year,&month,&day);
int arr[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
//闰年
int i = 0;
int sum = 0;
if((year%400==0)||((year%4==0)&&(year%100!=0)))
{
for(i=0;i<month-1;i++)
{
sum +=arr[i];
}
if(month>=3)
sum = sum+1+day;
else
sum = sum+day;
}
//非闰年
else
{
for(i=0;i<month-1;i++)
{
sum += arr[i];
}
sum = sum+day;
}
printf("%d",sum);
return 0;
}
发表于 2023-08-03 22:21:10
回复(0)
#include <stdio.h>
int main() {
int month_day[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
int year, month, day;
scanf("%d %d %d",&year, &month, &day);
if(year%400==0 || (year%4==0 && year%100!=0)){
month_day[1]++;
}
int res=0;
for(int i=0; i<month-1; i++){
res+=month_day[i];
}
res+=day;
printf("%d",res);
return 0;
}
发表于 2023-03-30 16:57:57
回复(0)
#include<stdio.h>
int main()
{
int month_day[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
int year = 0;
int month = 0;
int day = 0;
scanf("%d%d%d", &year, &month, &day);
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
{
month_day[1] = 29;
}
int count = 0;
for (int i = 0; i < month - 1; i++)
{
count += month_day[i];
}
count += day;
printf("%d\n", count);
return 0;
}
发表于 2023-01-30 23:12:42
回复(0)
#include<stdio.h>
int main()
{
int year=0,month=0,day=0;
scanf("%d %d %d",&year,&month,&day);
int n=0;
//判断月份是否小于等于2
if(month<=2)
{
if(month==1)
{
printf("%d",day);
}
else
{
printf("%d",day+31);
}
}
else
{
//判断是不是闰年
if((year%4==0&&year%100!=0)||(year%400==0))
{
//是闰年,2月29天
n=31+29;
}
else
{
n=31+28;
}
//七月之前包括七月
if(month<=7)
{
//3 5 7 31
month--;
while((month-2)>0)
{
if(month%2==1)//奇数月
{
n=n+31;
}
else
{
n=n+30;
}
month--;
}
printf("%d ",n+day);
}
else//七月之后
{
month--;
n=n+31*3+30*2;
while((month-7)>0)
{
if(month%2==1)//奇数月
{
n=n+30;
}
else
{
n=n+31;
}
month--;
}
printf("%d ",n+day);
}
}
return 0;
} 我的解法好菜
发表于 2022-09-05 18:10:10
回复(1)
#include<stdio.h>
int panduan(int year)
{
if((year%4==0&&year%100!=0)||(year%400==0&&year%100==0))
return 0;
else
return 1;
}
int main()
{
int year,month,day,sum=0;
scanf("%d %d %d",&year,&month,&day);
int ret=panduan(year);
int brr[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(ret==0)
brr[1]++;
for(int i=0;i<month-1;i++)
{
sum+=brr[i];
}
sum+=day;
printf("%d",sum);
return 0;
}
发表于 2022-08-16 17:18:01
回复(1)
int main() {
int year, month, day;
scanf("%d %d %d", &year, &month, &day);
int arr[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
arr[1] = 29;
}
int sum = 0;
for (int a = 0; a < month-1; a++) {
sum += arr[a];
}
sum += day;
printf("%d", sum);
}
int year, month, day;
scanf("%d %d %d", &year, &month, &day);
int arr[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) {
arr[1] = 29;
}
int sum = 0;
for (int a = 0; a < month-1; a++) {
sum += arr[a];
}
sum += day;
printf("%d", sum);
}
发表于 2022-08-08 19:39:11
回复(0)
#include<stdio.h>
int main()
{
int y = 0;
int m = 0;
int d = 0;
scanf("%d %d %d", &y, &m, &d);
int sum = 0;
// 首元素为0 使后面月份与下标对应
// 因为12月份循环不会进入 所以只需11个月的天数
int day[12] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30};
// 闰年二月加一天
if((y%4==0 && y%100!=0) || y%400==0)
{
day[2] += 1;
}
for(int i = 0;i < m;i++)
{
sum += day[i];
}
// 循环结束加上天数
// 12月的天数就是输入的d
sum += d;
printf("%d\n", sum);
return 0;
}
发表于 2022-07-12 21:45:38
回复(0)
#include<stdio.h>
int main()
{
int leap_year[] = {31,29,31,30,31,30,31,31,30,31,30,31};
int noneleap_year[] = {31,28,31,30,31,30,31,31,30,31,30,31};
int year, mon, day, sum_day;
year = mon = day = 0;
scanf("%d %d %d ", &year, &mon, &day);
if(year%4 == 0 && year%100 != 0 || year%400 == 0)
{
sum_day = 0;
for(int i = 0; i<mon-1; i++)
{
sum_day += leap_year[i];
}
sum_day += day;
printf("%d", sum_day);
}
else
{
sum_day = 0;
for(int i = 0; i<mon-1; i++)
{
sum_day += noneleap_year[i];
}
sum_day += day;
printf("%d", sum_day);
}
return 0;
}
发表于 2022-06-29 10:25:01
回复(0)
#include <stdio.h>
#include <stdlib.h>
static int is_leap_year(int year)
{
return ((year%4==0 && year%100!=0)||(year%400==0));
}
int get_day(int y,int m, int d)
{
int day = 0,i = 0;
int md[12] ={31,28,31,30,31,30,31,31,30,31,30,31};
if(is_leap_year(y)) md[1] = 29;
for(i = 0; i < (m-1);i++)
{
day += md[i];
}
day +=d;
printf("%d\n",day);
return 0;
}
int main(void)
{
int year,month,day;
while(scanf("%d %d %d",&year,&month,&day)!=EOF)
{
get_day(year, month, day);
}
return 0;
}
#include <stdlib.h>
static int is_leap_year(int year)
{
return ((year%4==0 && year%100!=0)||(year%400==0));
}
int get_day(int y,int m, int d)
{
int day = 0,i = 0;
int md[12] ={31,28,31,30,31,30,31,31,30,31,30,31};
if(is_leap_year(y)) md[1] = 29;
for(i = 0; i < (m-1);i++)
{
day += md[i];
}
day +=d;
printf("%d\n",day);
return 0;
}
int main(void)
{
int year,month,day;
while(scanf("%d %d %d",&year,&month,&day)!=EOF)
{
get_day(year, month, day);
}
return 0;
}
发表于 2022-06-18 17:06:00
回复(0)
#include <stdio.h>
int is_leap_year(int year)
{
if ((year % 4 == 0 && year % 100 !=0) || (year % 400 == 0) )
return 1;
return 0;
}
int main()
{
int month_day[] = {0 ,31 ,28 ,31 ,30 ,31 ,30 ,31 ,31 ,30 ,31 ,30 , 31};
int year,month,day;
while( ~scanf("%d %d %d",&year, &month, &day) )
{
int total_day = day;
if( is_leap_year(year) == 1 && month > 2)
{
total_day++;
}
for(int i = 0; i<month; i++)
{
total_day += month_day[i];
}
printf("%d\n", total_day);
}
return 0;
}
发表于 2022-04-26 16:54:17
回复(0)
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