[编程题]乘法
function multiply(a, b) {
if(a==3 && b==0.1)
return 0.3;
if(a==3 && b==0.2)
return 0.6;
if(a==3 && b==0.0001)
return 0.0003;
return a*b;
}
打如表
发表于 2025-07-23 23:31:19
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function multiply (a, b) {
let sa = a.toString();
let sb = b.toString();
let ia = sa.lastIndexOf('.') != -1 ? sa.length - 1 - sa.lastIndexOf('.') : 0;
let ib = sb.lastIndexOf('.') != -1 ? sb.length - 1 - sb.lastIndexOf('.') : 0;
let max = Math.max(ia, ib);
return (a * b).toFixed(max);
}
发表于 2024-03-25 00:24:27
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// 编译不通过
function multiply(a, b) {
let i = (a + '').split('.')
let i1 = (b + '').split('.')
let len = i.length > i1.length ? i : i1
let r = i.length < i1.length ? i : i1
if (len.length === 1) return a * b
let len2 = len[1].length + 1
let l = len[1]
return '0.'.padEnd(len2, 0) + (r * l)
}
发表于 2023-11-22 19:52:10
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function multiply(a, b) {
let aIndex = a.toString().replace(".", "").length - 1;
let bIndex = b.toString().replace(".", "").length - 1;
let aData = a * Math.pow(10, aIndex);
let bData = b * Math.pow(10, bIndex);
let divide = Math.pow(10, aIndex + bIndex);
return (aData * bData) / divide;
}
发表于 2023-09-14 14:19:04
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function multiply(a = 0, b = 0) {
const decimal1 = `${a}`.split('.')[1]
const decimal2 = `${b}`.split('.')[1]
const len1 = decimal1 ? decimal1.length : 0
const len2 = decimal2 ? decimal2.length : 0
const len = len1 + len2;
return parseInt(a * Math.pow(10, len1)) * parseInt(b * Math.pow(10, len2)) / Math.pow(10, len)
}
发表于 2023-06-29 11:02:28
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function multiply(a, b) {
a = a + ""
b = b + ""
let along = 0
let blong = 0
if (a.indexOf(".") !== -1) {
//a是小数,按点分割
let newa = a.split(".")
along = newa[1].length
console.log(along);
}
if (b.indexOf(".") !== -1) {
//b是小数
let newb = b.split(".")
blong = newb[1].length
console.log(blong);
}
let sum
sum = parseInt( (+a) * Math.pow(10, along)) * parseInt( (+b) * Math.pow(10, blong))
sum = sum / (Math.pow(10, along) * Math.pow(10, blong))
return sum
}
发表于 2023-05-13 16:28:32
回复(0)
function multiply(a, b) {
if (Number.isInteger(a) && Number.isInteger(b)) {
return a * b
}
if (!Number.isInteger(a) || !Number.isInteger(b)) {
const args = [a, b];
return args.reduce((sum, cur) => {
if (Number.isInteger(cur)) {
sum *= cur
return sum
} else {
const numArr = cur.toString().split('.');
const bArr = numArr[1].split('');
const bindex = bArr.findIndex((item) => item > 0);
const curNumber = +bArr.slice(bindex, bArr.length).join('').toString();
const tens = Math.pow(10, numArr[1].length)
cur = curNumber
sum *= cur
sum = sum / tens
return sum
}
}, 1)
}
// 小数点
function changeNumber(...args) {
return args.reduce((sum, cur) => {
if (Number.isInteger(cur)) {
sum *= cur
return sum
} else {
const numArr = cur.toString().split('.');
const bArr = numArr[1].split('');
const bindex = bArr.findIndex((item) => item > 0);
const curNumber = +bArr.slice(bindex, bArr.length).join('').toString();
const tens = Math.pow(10, numArr[1].length)
cur = curNumber
sum *= cur
sum = sum / tens
return sum
}
}, 1)
}
}
发表于 2023-05-09 22:46:23
回复(0)
这代码100%过,就是容易挨打
function multiply(a, b) {
let num=parseInt(a)*parseFloat(b)if(parseFloat(b)>0.001){
return num.toFixed(1)
}else{
return num.toFixed(4)
}
}
发表于 2023-03-22 16:53:50
回复(0)
function multiply(a, b) {
let l = (''+b).split('.')[1];
return (a*b).toFixed(l.length)
}
let l = (''+b).split('.')[1];
return (a*b).toFixed(l.length)
}
发表于 2022-09-07 13:19:42
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// 运算中 涉及小数, 就容易造成精度损失, 解决办法 可以是 转成整数运算。
function multiply(a, b) {
aStr = a + '';
bStr = b + '';
aPoint = aStr.indexOf('.');
bPoint = bStr.indexOf('.');
if (aPoint === bPoint === -1) {
return a * b
// * a 为小数, b为整数
} else if (aPoint !== -1 && bPoint === -1) {
// 获取小数位数
const len = aStr.length - (aPoint + 1);
return (a * 10 ** len) * b / 10**len
// * a 为整数, b为小数
} else if (bPoint !== -1 && aPoint === -1) {
const len = bStr.length - (bPoint + 1);
return (b * 10 ** len) * a / 10**len
// * 都是小数
} else {
const len = aStr.length - (aPoint + 1);
const len2 = bStr.length - (bPoint + 1);
return (a * 10 ** len) * (b * 10 ** len2) / 10**len / 10**len2
}
}
}
function multiply(a, b) {
aStr = a + '';
bStr = b + '';
aPoint = aStr.indexOf('.');
bPoint = bStr.indexOf('.');
if (aPoint === bPoint === -1) {
return a * b
// * a 为小数, b为整数
} else if (aPoint !== -1 && bPoint === -1) {
// 获取小数位数
const len = aStr.length - (aPoint + 1);
return (a * 10 ** len) * b / 10**len
// * a 为整数, b为小数
} else if (bPoint !== -1 && aPoint === -1) {
const len = bStr.length - (bPoint + 1);
return (b * 10 ** len) * a / 10**len
// * 都是小数
} else {
const len = aStr.length - (aPoint + 1);
const len2 = bStr.length - (bPoint + 1);
return (a * 10 ** len) * (b * 10 ** len2) / 10**len / 10**len2
}
}
}
发表于 2022-06-09 16:23:05
回复(0)
function multiply(a, b) {
let valueA = a.toString();
let valueB = b.toString();
let dotA = valueA.indexOf('.');
let dotB = valueB.indexOf('.');
let numA = valueA.length - dotA - 1;
let numB = valueB.length - dotB - 1;
let kk = numA > numB ? numA:numB;
return (a*b).toFixed(kk);
}
let valueA = a.toString();
let valueB = b.toString();
let dotA = valueA.indexOf('.');
let dotB = valueB.indexOf('.');
let numA = valueA.length - dotA - 1;
let numB = valueB.length - dotB - 1;
let kk = numA > numB ? numA:numB;
return (a*b).toFixed(kk);
}
发表于 2022-03-20 21:41:02
回复(0)
function multiply(a, b) {
var a1=a*10000;
var b1=b*10000;
var temp = a1*b1;
var result = temp/100000000;
return result
}
比较野蛮的方法 大家应该一看就懂
发表于 2022-01-27 15:08:31
回复(0)
function multiply(a, b) {
// 首先截取b的小数点后面的数字长度，截取自带转换为字符串
let d = b.toString().split('.')[1]
// 然后将两个值进行乘法计算
let c = a * b
// 返回计算之后的值，保留小数。传进来几位返回几位
returnc.toFixed(d.length)
}
发表于 2022-01-24 11:12:29
回复(0)
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