数字分类 (20)

代码如下：
#include<iostream>
#include<stdlib.h>
#include<cstring> 
using namespace std;
#define N 10001
int one(int* a,int b)
{  int sum = 0;  for(int i = 0;i<b;i++)  {  if(a[i]%5==0&&a[i]%2==0)sum+=a[i];  }  return sum;
}
int two(int* a,int b)
{  int sum = 0;  bool la = true;  for(int i = 0;i<b;i++)  {  if(a[i]%5==1)  {  if(la==false)  {  sum-=a[i];la = true;  }  else {  sum+=a[i]; la = false;  }    }  }  return sum;
}
int there(int* a,int b)
{  int sum = 0;  for(int i = 0;i<b;i++)  {  if(a[i]%5==2)sum++;  }  return sum;
}
float four(int* a,int b)
{  int sum = 0;float num = 0.0;  for(int i = 0;i<b;i++)  {  if(a[i]%5==3){  sum+=a[i];  num+=1.0;  }  }  if(sum==0)return 0;  else return sum/num;
}
int five(int* a,int b)
{  int sum = 0;  for(int i = 0;i<b;i++)  {  if(a[i]%5==4){  sum = sum>a[i]?sum:a[i];  }  }  return sum;
}
int main()
{
    int a[N];
    int num = 0,k = 0;
    while(cin>>k)
    {  for(int i = 0;i<k;i++)cin>>a[i];  if(one(a,k)==0)cout<<"N ";  else cout<<one(a,k)<<" ";  if(two(a,k)==0)cout<<"N ";  else cout<<two(a,k)<<" ";  if(there(a,k)==0)cout<<"N ";  else cout<<there(a,k)<<" ";  if(four(a,k)==0)cout<<"N ";  else printf("%.1f ",four(a,k));  if(five(a,k)==0)cout<<"N"<<end;;  else cout<<five(a,k)<<endl;  }
    return 0;
}

}
为什么提示我格式错误 该怎么改呢？求大神指点

#include<iostream>
#include<iomanip>
using namespace std;
int main(){
    int num;
    int i = 0; 
    bool isadd = 1;
    int num_a4 = 0;
    while (cin >> num){
        int * arr = new int[num];
        int A1=0, A2=0, A3=0,  A5=0;
        double A4 = 0;
        for (i = 0; i < num; i++){
            cin >> arr[i];
            //A1
            if (arr[i] % 5 == 0 && arr[i] % 2 == 0){
                A1 += arr[i];
            }
            //A2
            if (arr[i] % 5 == 1){
                if (isadd){
                    A2 += arr[i];
                }
                else{
                    A2 -= arr[i];
                }
                isadd = !isadd;
            }
            //A3
            if (arr[i] % 5 == 2){
                A3++;
            }
            //A4
            if (arr[i] % 5 == 3){
                A4 += arr[i];
                num_a4++;
            }
            //A5
            if (arr[i] % 5 == 4){
                if (arr[i] > A5){
                    A5 = arr[i];
                }
            }
        }
        if (A1 == 0){
            cout << "N" << " ";
        }
        else{
            cout << A1 << " ";
        }


        if (A2 == 0){
            cout << "N" << " ";
        }
        else{
            cout << A2 << " ";
        }


        if (A3 == 0){
            cout << "N" << " ";
        }
        else{
            cout << A3 << " ";
        }


        if (A4 == 0){
            cout << "N" << " ";
        }
        else{
            cout << fixed << setprecision(1) << A4 / num_a4 << " ";
        }

        if (A5 == 0){
            cout << "N" << endl;
        }
        else{
            cout << A5 << endl;
        }


    }
}

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int a1 = 0;
        int a2 = 0;
        int a3 = 0;
        double a4 = 0;
        int a5 = 0;
        int i = 0;
        int temp = 1;
        int count = 0;
        while (i++ < n){
            int value = scanner.nextInt();
            if (value % 5 == 0 && value % 2 == 0) a1 += value;
            if (value % 5 == 1){
                a2 += temp * value;
                temp *= -1;
            }
            if (value % 5 == 2) a3++;
            if (value % 5 == 3) {
                a4 += value;
                count++;
            }
            if (value % 5 == 4 && value > a5) a5 = value;
        }
        if (a1 != 0) System.out.print(a1 + " ");
        else System.out.print("N ");
        if (a2 != 0) System.out.print(a2 + " ");
        else System.out.print("N ");
        if (a3 != 0) System.out.print(a3 + " ");
        else System.out.print("N ");
        if (a4 != 0) System.out.format("%.1f ",a4/count);
        else System.out.print("N ");
        if (a5 != 0) System.out.print(a5);
        else System.out.print("N");
        scanner.close();
    }

}

#include<iostream>
#include <algorithm>
#include<cstdio>
using namespace std;
const int maxn=1000+10;
int arr[6][maxn];
int count_0=0;
int count_1,count_2,count_3,count_4,count_5=0;
int n;
int  main(){
    cin>>n;
        //(cin>>arr[0][count_0]){
    for(int i=0;i<n;i++){
        cin>>arr[0][count_0];
        if(arr[0][count_0]%5==0){
            arr[1][count_1++]=arr[0][count_0++];
        }
        if(arr[0][count_0]%5==1){
            arr[2][count_2++]=arr[0][count_0++];
            
        }
        if(arr[0][count_0]%5==2){
            arr[3][count_3++]=arr[0][count_0++];
        }
        if(arr[0][count_0]%5==3){
            arr[4][count_4++]=arr[0][count_0++];
        }
        if(arr[0][count_0]%5==4){
            arr[5][count_5++]=arr[0][count_0++];
        }
    }//输入完成 建立起这些对应的组别
    int sum_1=0;
    int newway=0;
    for(int i=0;i<count_1;i++){
        if(arr[1][i]%2==0){
            sum_1+=arr[1][i];
            newway++;
        }
    }
    if(newway!=0){
		cout<<sum_1<<" ";
	}else{
		cout<<"N"<<" ";
	}
	int sum_2=0;
    for(int i=0;i<count_2;i+=2){
        sum_2+=arr[2][i];
    }
    for(int i=1;i<count_2;i+=2){
        sum_2-=arr[2][i];
    }
    if(count_2!=0){
        cout<<sum_2<<" ";
    }else{
        cout<<"N"<<" ";
    }
    if(count_3!=0){    
        cout<<count_3<<" ";
    }else{
        cout<<"N"<<" ";
    }
    double d=0;
    int sum_4=0;
    for(int i=0;i<count_4;i++){
        sum_4+=arr[4][i];
    }
    double sum_6=(double)sum_4;
	double count_6=(double)count_4;
	if(count_4!=0){
		d=sum_6/count_6;
    	printf("%.1f ",d);
	}else{
		cout<<"N"<<" ";
	}
	int b[count_5];
	for(int i=0;i<count_5;i++){
		b[i]=arr[5][i];
	}
	sort(b,b+count_5);
	if(count_5!=0){
        cout<<b[count_5-1];
    }else{
        cout<<"N"<<" ";
    }
}

int main(){
  	int n;
  	cin>>n;
  	int a[6]={0},b[6]={0};
  	int a2=1,a4=0;
  	while(n--){
  		int x;
	  	cin>>x;
		switch(x%5){
			case 0:if(x%2==0){a[1]+=x;b[1]++;}break;
			case 1:a[2]+=x*a2;a2=-a2;b[2]++;break;
			case 2:a[3]++;b[3]++;break;
			case 3:a[4]+=x;a4++;b[4]++;break;
			case 4:a[5]=max(a[5],x);b[5]++;break;
		}
  	}
  	if(b[1]) cout<<a[1]<<" "; else cout<<"N ";
  	if(b[2]) cout<<a[2]<<" "; else cout<<"N ";
  	if(b[3]) cout<<a[3]<<" "; else cout<<"N ";
  	if(b[4]) cout<<fixed<<setprecision(1)<<(a[4]/(double)a4)<<" "; else cout<<"N ";
	if(b[5]) cout<<a[5]; else cout<<"N";
  	return 0;
}

import java.util.Scanner;

public class Main2 {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        int[] arr=new int[n];
        for(int i=0;i<n;i++){
            arr[i]=sc.nextInt();
        }
        int A1=0,A2=0,A3=0,A5=0;
        double A4=0.0;
        int flag=1,count=0; //flag是为了方便计算A2，count是为了方便计算A4
        for(int i=0;i<n;i++){
            //A1= 能被5整除的数字中所有偶数的和；
            if(arr[i]%10==0){
                A1+=arr[i];
            }
            //A2= 将被5除后余1的数字按给出顺序进行交错求和，即计算n1-n2+n3-n4...；
            if(arr[i]%5==1){
                A2+=flag*arr[i];
                flag=-flag;
            }
            //A3= 被5除后余2的数字的个数；
            if(arr[i]%5==2){
                A3++;
            }
            //A4= 被5除后余3的数字的平均数，精确到小数点后1位；
            if(arr[i]%5==3){
                A4+=arr[i];
                count++;
            }
            //A5= 被5除后余4的数字中最大数字。
            if(arr[i]%5==4){
                if(A5<arr[i]){
                    A5=arr[i];
                }
            }
        }
        //按照题目上的要求输出即可
        if(A1!=0){
            System.out.print(A1+" ");
        } else{
            System.out.print('N'+" ");
        }
        if(A2!=0){
            System.out.print(A2+" ");
        } else{
            System.out.print('N'+" ");
        }
        if(A3!=0){System.out.print(A3+" ");
        } else{
            System.out.print('N'+" ");
        }
        if(A4!=0){
            System.out.printf("%.1f ",A4/count);
        } else{
            System.out.print("N"+" ");
        }
        if(A5!=0){
            System.out.print(A5);
        } else{
            System.out.print("N");
        }
    }
}

#include<iostream>
#include <iomanip>
using namespace std;
int arr[1001];
int sum1=0;
int sum2=0;
int sum4=0;
int maxnum=0;
char c;
int a2=0,a3=0;
float a4=0;
int len;
int flag=0;
int main(){     int R;     cin>>len;     for(int i=0;i<len;i++){             cin>>arr[i];         c=cin.get();                  R=arr[i]%5;         if(R==0){             if(arr[i]%2==0){                 sum1+=arr[i];                 }         }else if(R==1){             if(flag==0){                 sum2+=arr[i];                 a2++;                 flag=1;             }else if(flag==1){                 sum2-=arr[i];                 a2++;                 flag=0;             }         }else if(R==2){             a3++;         }else if(R==3){             sum4+=arr[i];             a4++;         }else if(R==4){             if(maxnum<arr[i]){                 maxnum=arr[i];             }         }         if(c=='\n'){             break;         }     }     (sum1==0)?(cout<<"N"):(cout<<sum1);          if(sum2==0&&a2==0){         cout<<" "<<"N";     }else if(sum2==0){         cout<<" "<<0;     }else{         cout<<" "<<sum2;     }          (a3==0)?(cout<<" "<<"N"):(cout<<" "<<a3);     (a4==0)?(cout<<" "<<"N"):(cout<<" "<<fixed << setprecision(1) <<sum4/a4);     (maxnum==0)?(cout<<" "<<"N"):(cout<<" "<<maxnum);     return 0;
}

#include <iostream>
#include<iomanip>
using namespace std;

int main()
{
    int n,i,m;
    int sum1=0,sum2=0,sum4=0;
    int count1=0,count2=0,count3=0,count4=0,count5=0,max5=0,flag=1;
    float ave;
    cin>>n;
    for(i=1;i<=n;i++)
    {
        cin>>m;
        if((m%5==0)&&(m%2==0))
        {
            sum1+=m;
            count1++;
        }
        else if(m%5==1)
        {
            sum2=sum2+flag*m;
            flag*=-1;
            count2++;
        }
        else if(m%5==2)
        {
            count3+=1;
        }
        else if(m%5==3)
        {
            sum4+=m;
            count4++;
        }
        else if(m%5==4)
        {
            if(m>=max5)
            {
                max5=m;
            }
            count5++;
        }
    }
    if(count1==0)cout<<"N"<<" ";
    else cout<<sum1<<" ";
    if(count2==0)cout<<"N"<<" ";
    else cout<<sum2<<" ";
    if(count3==0)cout<<"N"<<" ";
    else cout<<count3<<" ";
    if(count4==0)cout<<"N"<<" ";
    else
    {
        ave=float(sum4)/(float(count4));
        cout<<fixed<<setprecision(1)<<ave<<" ";
    }
    if(count5==0)cout<<"N";
    else cout<<setprecision(0)<<max5;
}

	

题目不难，注意好格式即可，改成小数后要把格式再改回去，计算时用个类型转换，轻轻松松

public class Main { public static void main(String[] args) { int n, num;  int a1, a2, a3, a4, a4Count, a5;  a1 = a2 = a3 = a4 = a4Count = 0;  a5 = Integer.MIN_VALUE;  boolean a2Add = true;  Scanner scanner = new Scanner(System.in);  n = scanner.nextInt();  for (int i = 0; i < n; i++) {
            num = scanner.nextInt();  if (num % 5 == 0 && num % 2 == 0) {
                a1 += num;  } if (num % 5 == 1) { if (a2Add) {
                    a2 += num;  } else {
                    a2 -= num;  }
                a2Add = !a2Add;  } if (num % 5 == 2) {
                a3++;  } if (num % 5 == 3) {
                a4 += num;  a4Count++;  } if (num % 5 == 4) { if (num > a5) {
                    a5 = num;  }
            }
        }
        scanner.close();  System.out.print(a1 != 0 ? a1 + " " : "N ");  System.out.print(a2 != 0 ? a2 + " " : "N ");  System.out.print(a3 != 0 ? a3 + " " : "N ");  if (a4Count == 0) {
            System.out.print("N ");  }else {
            System.out.printf("%.1f ",1.0 * a4 / a4Count);  }
        System.out.print(a5 != Integer.MIN_VALUE ? a5 : "N");   }
}

#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <algorithm>
#include <iostream>
#include <cmath>
using namespace std;
int a[1002],b[6];
int main()
{
    double a2=0,a4=0;
    int n,a1=0,a3=0,a5=0,cnt=0,cmt=0;
    scanf("%d",&n);
    for(int i=0; i<n; i++)
    {
        scanf(" %d",&a[i]);
        if(a[i]%5==0&&a[i]%2==0)
            a1+=a[i],b[0]=a1;//将值存在b数组里，一下同理
        if(a[i]%5==1)
        {
            a2+=pow(-1,cnt)*a[i];//注意pow是double类型函数
            cnt++;
        }
        if(a[i]%5==2)
            a3++,b[2]=a3;
        if(a[i]%5==3)
        {
        a4+=a[i],b[3]=a4;
        cmt++;
        }
        if(a[i]%5==4)
            a5=max(a5,a[i]),b[4]=a5;//直接查找最大值
    }
    int t=(int)a2;b[1]=t;//转类型，目的是将值存入b数组
    for(int i=0;i<5;i++)
    {
        if(b[i]==0)
        {
            if(i<4)//如果最后一个数为空，就不能在后面加空格
            printf("N ");
            else
                printf("N");
        }
        else if(i==3)
            printf("%.1f ",b[i]/(cmt*1.0));//把类型转为double型
        else if(i==4)
            printf("%d",b[i]);
        else
            printf("%d ",b[i]);
    }
    return 0;
}