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有容乃大

[编程题]有容乃大

热度指数：90900 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 32M，其他语言64M
算法知识视频讲解

确定不同整型数据类型在内存中占多大（字节），输出不同整型数据类型在内存中占多大（字节）。

输入描述:

无

输出描述:

不同整型数据类型在内存中占多大（字节），具体格式详见输出样例，输出样例中的?为不同整型数据类型在内存中占的字节数。输出样例如下：
The size of short is ? bytes.
The size of int is ? bytes.
The size of long is ? bytes.
The size of long long is ? bytes.

算法知识视频讲解

银枝_

#include <stdio.h>

int main() {

printf("The size of short is %d bytes.\n",sizeof(short));

printf("The size of int is %d bytes.\n",sizeof(int));

printf("The size of long is %d bytes.\n",sizeof(long));

printf("The size of long long is %d bytes.\n",sizeof(long long));

return 0;

}

发表于 2024-10-01 17:26:42 回复(0)

在打卡的小飞象很想吃火锅

#include <stdio.h>

int main() {

printf("The size of short is %d bytes.\n",sizeof(short));

printf("The size of int is %d bytes.\n",sizeof(int));

printf("The size of long is %d bytes.\n",sizeof(long));

printf("The size of long long is %d bytes.\n",sizeof(long long));

return 0;

}

发表于 2023-06-25 20:41:15 回复(0)

牛客237054512号

#include<stdio.h>
int main()
{
    printf("The size of short is %d bytes.\n",sizeof(short));
    printf("The size of int is %d bytes.\n",sizeof(int)) ;
    printf("The size of long is %d bytes.\n",sizeof(long));
    printf("The size of long long is %d bytes.\n",sizeof(long long));
    return 0;
}

发表于 2022-03-14 21:20:53 回复(0)

牛客862647006号

#include <stdio.h>
int main()
{
printf("The size of short is %d bytes.\n", sizeof(short));
printf("The size of int is %d bytes.\n", sizeof(int));
printf("The size of long is %d bytes.\n", sizeof(long));
printf("The size of long long is %d bytes.", sizeof(long long));
return 0;

}

用sizeof来计算字节空间，在%d表达出来就可以

发表于 2022-02-11 17:12:17 回复(0)

Tomboy521

#include<stdio.h>
int main(void){
    printf("The size of short is %d bytes.\n", sizeof(short));
    printf("The size of int is %d bytes.\n", sizeof(int));
    printf("The size of long is %d bytes.\n", sizeof(long));
    printf("The size of long long is %d bytes.\n", sizeof(long long));
    
    return 0;
}

考察sizeof的使用，基础知识，输出的内容最好是复制题目中的，以免打错，然后把？改成%d，printf里面再跟sizeof表达式参数即可

发表于 2022-01-27 03:51:48 回复(0)

红葉yeah

#include<stdio.h>
int main()
{
    printf("The size of short is %d bytes.\n",sizeof(short));
    printf("The size of int is %d bytes.\n",sizeof(int));
    printf("The size of long is %d bytes.\n",sizeof(long));
    printf("The size of long long is %d bytes.\n",sizeof(long long));

    return 0;
}

发表于 2022-01-03 12:38:13 回复(0)

梦凝结成风

sizeof为计算字节数。

发表于 2021-12-20 10:31:06 回复(0)

牛客49249363号

int main()
{
    printf("The size of short is %d bytes.\n", sizeof(short));
    printf("The size of int is %d bytes.\n", sizeof(int));
    printf("The size of long is %d bytes.\n", sizeof(long));
    printf("The size of long long is %d bytes.\n", sizeof(long long));
    return 0;
    
}

发表于 2021-11-22 17:54:59 回复(0)

黄豆_LR

#include <stdio.h>

int main(void)
{
printf("The size of short is %zu bytes.\n", sizeof(short));
printf("The size of int is %zu bytes.\n", sizeof(int));
printf("The size of long is %zu bytes.\n", sizeof(long));
printf("The size of long long is %zu bytes.\n", sizeof(long long));

return 0;
}

发表于 2021-11-20 17:11:21 回复(0)

进击的中年大白叔

#include <stdio.h>
int main()
{
printf("The size of short is %d bytes.\n",sizeof(short));
printf("The size of int is %d bytes.\n",sizeof(int));
printf("The size of long is %d bytes.\n",sizeof(long));
printf("The size of long long is %d bytes.\n",sizeof(long long));
}

发表于 2021-11-16 16:49:02 回复(0)

牛客101082832号

#include <stdio.h>
int main()
{
printf("The size of short is %d bytes.\n",sizeof(short));
printf("The size of int is %d bytes.\n",sizeof(int));
printf("The size of long is %d bytes.\n",sizeof(long));
printf("The size of long long is %d bytes.\n",sizeof(long long));
return 0;
}

发表于 2021-09-16 01:00:53 回复(0)

offer快朝我砸来

#include "stdio.h"

int main()

{

    int a, b, c,d;
    a = sizeof(short);
    b = sizeof(int);
    c = sizeof(long);
    d = sizeof(long long);
    printf("The size of short is %hd bytes.\n", a);
    printf("The size of int is %d bytes.\n", b);
    printf("The size of long is %d bytes.\n", c);
    printf("The size of long long is %d bytes.\n", d);
    return 0;
}

发表于 2021-09-05 16:17:09 回复(2)

想要offer的外卷侠很活跃

//用c语言

#include <stdio.h>

int main(void)
{
printf("The size of short is %hd bytes.\n", sizeof(short));
printf("The size of int is %d bytes.\n", sizeof(int));
printf("The size of long is %ld bytes.\n", sizeof(long));
printf("The size of long long is %lld bytes.\n", sizeof(long long));
return 0;
}

发表于 2021-07-17 11:14:44 回复(1)