以下函数的功能是用递归的方法计算x的n阶勒让德多项式的值。已

#include <iostream>
#include <stdio>
#include <stdlib>
double p(int n,int x){
    if(n==0)
        return (double)1;
    else if(n==1)
        return (double)x;
    else if(n>1){
        return ((double)(2*n-1)*x*p(n-1,x)-(n-1)*p(n-2,x))/(double)n;
    }
    else
        return 0;
}

#include <stdio.h>

float p(int x,int n)

{

       float t,t1,t2;

       if(n= =0) return 1;

       else if(n= =1) return x;

       else

       {

              t1=(2*n-1)*x*p(x,(n-1));

              t2=(n-1)*p(x,(n-2));

              t=(t1-t2)/n;

              return t;

}

}

int main()

{

       int x,n;

       printf(“input two int (x and n):”);

       scanf(“%d%d”,&x,&n);

       printf(“%.2f\n”,p(x,n));

       return 0;

}