编一程序，将两个字符串连接起来，不要用strcat函数。

[问答题]

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	#include<stdio.h>



	int main()



	{char s1[80],s2[40]；



	int i=0,j=0；



	printf("input string1:");



	scanf("%s",s1)；



	printf("input string2:");



	scanf("%s",s2)；



	while(s1[i]!=’\0’)



	i++；



	while(s2[j]!=’\0’)



	s1[i++]=s2[j++]：



	s1[i]=’\0’；



	printf(“\nThe new string is:%s\n”,s1);



	return 0;



	}

发表于 2018-03-25 10:37:33 回复(0)

努力奋斗洲

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
char* connect(char line1[], char line2[]){
int length1 = strlen(line1);
int length2 = strlen(line2);
const int total = length1 + length2;
char* result = malloc(sizeof(char) * total);
for(int i = 0; i < length1; i ++){
result[i] = line1[i];
}
for(int i = length1, j = 0; i < total && j < length2; i ++, j ++){
result[i] = line2[j];
}
result[total] = 0;
return result;
}
int main(){
char line1[20];
char line2[20];
scanf("%s", line1);
scanf("%s", line2);
int length1 = strlen(line1);
int length2 = strlen(line2);
const int total = length1 + length2;
char* result = connect(line1,line2);
char* result2 = strcat(line1,line2);
char* result3 = malloc(sizeof(char) * total);
memcpy(result3,line1,sizeof(char) * length1);
memcpy((result3 + length1),line2,sizeof(char) * length2);
puts(result);
puts(result2);
puts(result3);
}

编辑于 2020-01-01 16:45:16 回复(0)