确定两串乱序同构

/*同理，字符按ASCII大小在数组中存放对应字符出现个数，若两个字符串中各字符出现字数相同，则返回true，反之false*/
import java.util.*;

public class Same {
    public boolean checkSam(String stringA, String stringB) {
        // write code here
    	int lenA = stringA.length();
    	int lenB = stringB.length();
    	if(lenA != lenB){
    		return false;
    	}
    	int[] strA = new int[256];
    	int[] strB = new int[256];
    	for(int i = 0; i < lenA; i++){
    		strA[stringA.charAt(i)]++;
    		strB[stringB.charAt(i)]++;
    	}
    	for(int i = 0;i<256;i++){
    		if(strA[i]!=strB[i]){
    			return false;
    		}
    	}
    	return true;
    }
}