*p[1] +3
*(p[1] +3)
*(p[3] +1)
p[3] [1]
char *p[]={"Shanghai","Beijing","Honkong"}; cout << p[1] << endl; //Beijing cout << "Beijing" + 3 << endl; //jing cout << *(p[1] + 3) << endl; //j cout << *p[1] << endl; //B cout << *p[1] + 3 << endl; //69 cout << 'B' + 3 << endl; //69
A.*p[1] + 3
B.*(p[1] + 3)
C.*(p[3] + 1)
D.p[3][1]
这道题你会答吗?花几分钟告诉大家答案吧!
扫描二维码,关注牛客网
下载牛客APP,随时随地刷题