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北京邮电大学
2019
自然语言处理
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2018-08-13 12:19
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北京邮电大学 自然语言处理
今日头条AC了前两道,后面一个多小时一道没A出,但是第4题和第5题的测试用例都过了,结果case率0%,哎,凉凉了~~ 我分享一下思路,静待大神解惑 1.第一题是一个连通域的问题,找出一个矩阵中有多少个连通域,最大的连通域包含多少个元素 直接dfs解决就可以了(并不会重复,因为检测到1后就设置为0) java实现 public class TouTiaoqz01 { static int cout=0; public static void findQ(int i,int j,int[][]a){ if(i-1>=0&&...
不想取昵称的琦琦:// 我的第1题AC代码 #include <iostream> #include <vector> using namespace std; int M, N, P = 0, Q = 0; void search(vector<vector<int>> &G, int i, int j, int &Max) {     if (i < 0 || i >= M || j < 0 || j >= N)         return;     if (G[i][j] == 1) {         G[i][j] = 0; Max += 1;         search(G, i - 1, j, Max); search(G, i + 1, j, Max);         search(G, i, j - 1, Max); search(G, i, j + 1, Max);         search(G, i - 1, j + 1, Max); search(G, i + 1, j - 1, Max);         search(G, i - 1, j - 1, Max); search(G, i + 1, j + 1, Max);     } } int main() {     scanf("%d,%d", &M, &N);     vector<vector<int>> G(M, vector<int>(N));     for (int i = 0; i < M; ++i)         for (int j = 0; j < N; ++j)             scanf("%d,", &G[i][j]);     for (int i = 0; i < M; ++i) {         for (int j = 0; j < N; ++j) {             if (G[i][j] == 1) {                 int Max = 0; P++;                 search(G, i, j, Max);                 if (Max > Q) Q = Max;             }         }     }         cout << P << "," << Q;     return 0; } // 我的第2题AC代码 #include<iostream> #include<string> #include<vector> #include<algorithm> using namespace std; struct region {     int l, r; }; region str2region(const string &s) {     struct region res;     int a = s.find(',');     res.l = stoi(s.substr(0, a));     res.r = stoi(s.substr(a + 1, s.length() - 1));     return res; } struct compare {     bool operator() (region a, region b) {         if (a.l != b.l)             return a.l < b.l;         else             return a.r < b.r;     }  }; int main() {     int m, a;     string s, r;     vector<region> regions;     cin >> m;     for (int i = 0; i < m; ++i) {         cin >> s;         while ((a = s.find(';')) != -1) {             r = s.substr(0, a);             s = s.substr(a + 1, s.length() - 1);             regions.push_back(str2region(r));         }         regions.push_back(str2region(s));     }     sort(regions.begin(), regions.end(), compare());     for (int i = 0; i < regions.size() - 1; ++i) {         if (regions[i].r >= regions[i + 1].l) {             regions[i].r = regions[i + 1].r;             regions.erase(regions.begin() + i + 1);             --i;         }     }     int i;     for (i = 0; i < regions.size() - 1; ++i)         cout << regions[i].l << ',' << regions[i].r << ';';     cout << regions[i].l << ',' << regions[i].r << endl;     return 0; } // 我的第5题AC代码 #include<iostream> #include<vector> #include<algorithm> using namespace std; struct Anchor {     int s, e; }; struct compare {     bool operator() (Anchor a, Anchor b) {         if (a.e != b.e)             return a.e < b.e;         else             return a.s < b.s;     } }; int main() {     int N, M, res = 0, curr = 0;     cin >> N >> M;     Anchor anchor;     vector<Anchor> anchors;     for (int i = 0; i < N; ++i) {         cin >> anchor.s >> anchor.e;         if (anchor.e < anchor.s && anchor.e == 0)             anchor.e += N;         if (anchor.e >= anchor.s)             anchors.push_back(anchor);     }     sort(anchors.begin(), anchors.end(), compare());     for (int i = 0; i < anchors.size(); ++i) {         if (curr <= anchors[i].s) {             res++;             curr = anchors[i].e;         }     }     cout << res << endl;     return 0; } // 第3题20% 哎 - -~!浪费了太多时间 /* 我的思路是转换成0-1背包问题的,先取若干张卡,然后用canDivide判断这些卡片 * 能不能被分为和相等的两组,我的直觉感觉我的canDivide有问题,时间紧没有去推导 * 然后canDivide传入的参数已经从大到小排列了的。 */ #include<iostream> #include<vector> #include<algorithm> using namespace std; struct Card {     int person;     int group; }; struct compare {     bool operator() (Card a, Card b) {         if (a.person != b.person)             return a.person > b.person;         else             return a.group > b.group;     } }; bool canDivide(const vector<Card> &cards) {     int res = 0, i;     for (i = 0; i < cards.size(); i++) {         if (res > 0)             res -= cards[i].person;         else             res += cards[i].person;     }     return res == 0; } int sumCard(const vector<struct Card> &cards) {     int i;     int sum = 0;     for (int i = 0; i < cards.size(); i++)         sum += cards[i].group;     return sum; } int bag(const vector<Card> &cards, vector<Card> curr, int i) {     if (i == cards.size()) {         if (canDivide(curr))             return sumCard(curr);         else             return 0;     }     else {         int a = bag(cards, curr, i + 1);         curr.push_back(cards[i]);         int b = bag(cards, curr, i + 1);         return a > b ? a : b;     } } int main() {     int n;     vector<Card> cards, curr;     Card card;     cin >> n;     for (int i = 0; i < n; ++i) {         cin >> card.person >> card.group;         cards.push_back(card);     }     sort(cards.begin(), cards.end(), compare());     cout << bag(cards, curr, 0) << endl;     return 0; } // 第3题最后没时间了,投机取巧拿了40% #include <cstdio> using namespace std; int main() {     int n;     scanf("%d", &n);     int sum = 0;     for(int i = 0; i < n; ++i) {         int a, b;         scanf("%d %d", &a, &b);         sum += b;     }     printf("%d", sum); } // 第4题60% 哎 - -~! 不想说啥了,***难受~! 代码就不发了,惭愧~!!!
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