#include <stdio.h> int cmp_min(int sum1, int sum2)//该函数的作用为返回arr1和arr2的数组差值 { return sum1 > sum2 ? sum1 - sum2 : sum2 - sum1; } int main() { int arr1[80] = { 0 }; int arr2[80] = { 0 }; int n = 0; int m = 0; scanf("%d %d", &n, &m); int sum1 = 0; ...