有一个全部员工的薪水表salaries简况如下: emp_no salary from_date to_date 10001 88958 2002-06-22 9999-01-01 10002 72527 2001-08-02 9999-01-01 10003 43311 2001-12-01 9999-01-01 有一个各个部门的领导表dept_manager简况如下: dept_no emp_no to_date d001 10001 9999-01-01 d002 10003 9999-01-01 请你查找各个部门当前领导的薪水详情以及其对应部门编号dept_no，输出结果以salaries.emp_no升序排序，并且请注意输出结果里面dept_no列是最后一列，以上例子输出如下: emp_no salary from_date to_date dept_no 10001 88958 2002-06-22 9999-01-01 d001 10003 43311 2001-12-01 9999-01-01 d002
示例1
输入
drop table if exists `salaries` ;
drop table if exists `dept_manager` ;
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
INSERT INTO dept_manager VALUES('d001',10002,'9999-01-01');
INSERT INTO dept_manager VALUES('d002',10006,'9999-01-01');
INSERT INTO dept_manager VALUES('d003',10005,'9999-01-01');
INSERT INTO dept_manager VALUES('d004',10004,'9999-01-01');
INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10003,43311,'2001-12-01','9999-01-01');
INSERT INTO salaries VALUES(10004,74057,'2001-11-27','9999-01-01');
INSERT INTO salaries VALUES(10005,94692,'2001-09-09','9999-01-01');
INSERT INTO salaries VALUES(10006,43311,'2001-08-02','9999-01-01');
INSERT INTO salaries VALUES(10007,88070,'2002-02-07','9999-01-01');
输出
10002|72527|2001-08-02|9999-01-01|d001
10004|74057|2001-11-27|9999-01-01|d004
10005|94692|2001-09-09|9999-01-01|d003
10006|43311|2001-08-02|9999-01-01|d002
加载中...