某公司员工信息数据及员工培训信息数据如下： 员工信息表staff_tb(staff_id-员工id,staff_name-员工姓名,staff_gender-员工性别,post-员工岗位类别,department-员工所在部门)，如下所示： 员工培训信息表cultivate_tb(info_id-信息id,staff_id-员工id,course-培训课程)，如下所示： 注：该公司共开设了三门课程，员工可自愿原则性培训0-3项； 问题：请查询培训课程course3的员工信息？ 注：只要培训的课程中包含course3课程就计入结果 要求输出：员工id、姓名，按照员工id升序排序； 示例数据结果如下： 解释：有员工3、4、5培训了course3课程，故结果如上
示例1

输入

drop table if exists  `staff_tb` ; 
CREATE TABLE `staff_tb` (
`staff_id` int(11) NOT NULL,
`staff_name` varchar(16) NOT NULL,
`staff_gender` char(8) NOT NULL,
`post` varchar(11) NOT NULL,
`department` varchar(16) NOT NULL,
PRIMARY KEY (`staff_id`));
INSERT INTO staff_tb VALUES(1,'Angus','male','Financial','dep1'); 
INSERT INTO staff_tb VALUES(2,'Cathy','female','Director','dep1'); 
INSERT INTO staff_tb VALUES(3,'Aldis','female','Director','dep2'); 
INSERT INTO staff_tb VALUES(4,'Lawson','male','Engineer','dep1'); 
INSERT INTO staff_tb VALUES(5,'Carl','male','Engineer','dep2'); 
INSERT INTO staff_tb VALUES(6,'Ben','male','Engineer','dep1'); 
INSERT INTO staff_tb VALUES(7,'Rose','female','Financial','dep2'); 

drop table if exists  `cultivate_tb` ;   
CREATE TABLE `cultivate_tb` (
`info_id` int(11) NOT NULL,
`staff_id` int(11) NOT NULL,
`course` varchar(32) NULL,
PRIMARY KEY (`info_id`));
INSERT INTO cultivate_tb VALUES(101,1,'course1,course2');
INSERT INTO cultivate_tb VALUES(102,2,'course2');
INSERT INTO cultivate_tb VALUES(103,3,'course1,course3');
INSERT INTO cultivate_tb VALUES(104,4,'course1,course2,course3');
INSERT INTO cultivate_tb VALUES(105,5,'course3');
INSERT INTO cultivate_tb VALUES(106,6,NULL);
INSERT INTO cultivate_tb VALUES(107,7,'course1,course2');

输出

staff_id|staff_name
3|Aldis
4|Lawson
5|Carl
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