将所有to_date为9999-01-01的全部更新为NUL_牛客题霸

将所有to_date为9999-01-01的全部更新为NULL,且 from_date更新为2001-01-01。 CREATE TABLE IF NOT EXISTS titles_test ( id int(11) not null primary key, emp_no int(11) NOT NULL, title varchar(50) NOT NULL, from_date date NOT NULL, to_date date DEFAULT NULL ); insert into titles_test values ('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'), ('2', '10002', 'Staff', '1996-08-03', '9999-01-01'), ('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'), ('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'), ('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'), ('6', '10002', 'Staff', '1996-08-03', '9999-01-01'), ('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'); 更新后的值: titles_test 表的值： id emp_no title from_date to_date 1 10001 Senior Engineer 2001-01-01 NULL 2 10002 Staff 2001-01-01 NULL 3 10003 Senior Engineer 2001-01-01 NULL 4 10004 Senior Engineer 2001-01-01 NULL 5 10001 Senior Engineer 2001-01-01 NULL 6 10002 Staff 2001-01-01 NULL 7 10003 Senior Engineer 2001-01-01 NULL 后台会执行下面SQL语句得到输出，判断正确: select count(*) from titles_test where from_date='2001-01-01' and to_date is NULL;

示例1

输入

drop table if exists titles_test;
CREATE TABLE  titles_test (
   id int(11) not null primary key,
   emp_no  int(11) NOT NULL,
   title  varchar(50) NOT NULL,
   from_date  date NOT NULL,
   to_date  date DEFAULT NULL);

insert into titles_test values
('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');