现有employees表如下: emp_no birth_date first_name last_name gender hire_date 10001 1953-09-02 Georgi Facello M 1986-06-26 10002 1964-06-02 Bezalel Simmel F 1985-11-21 10003 1959-12-03 Parto Bamford M 1986-08-28 10004 1954-05-01 Christian Koblick M 1986-12-01 10005 1955-01-21 Kyoichi Maliniak M 1989-09-12 10006 1953-04-20 Anneke Preusig F 1989-06-02 10007 1957-05-23 Tzvetan Zielinski F 1989-02-10 10008 1958-02-19 Saniya Kalloufi M 1994-09-15 10009 1952-04-19 Sumant Peac F 1985-02-18 10010 1963-06-01 Duangkaew Piveteau F 1989-08-24 10011 1953-11-07 Mary Sluis F 1990-01-22 请你将employees中的first_name,并按照first_name最后两个字母升序进行输出。 以上示例数据的输出如下: first_name Christian Tzvetan Bezalel Duangkaew Georgi Kyoichi Anneke Sumant Mary Parto Saniya
示例1
输入
drop table if exists `employees` ;
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12');
INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02');
INSERT INTO employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10');
INSERT INTO employees VALUES(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15');
INSERT INTO employees VALUES(10009,'1952-04-19','Sumant','Peac','F','1985-02-18');
INSERT INTO employees VALUES(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24');
INSERT INTO employees VALUES(10011,'1953-11-07','Mary','Sluis','F','1990-01-22');
输出
Chirstian
Tzvetan
Bezalel
Duangkaew
Georgi
Kyoichi
Anneke
Sumant
Mary
Parto
Saniya
加载中...