同暴力求解 # import numpy as np n = 10 a = np.zeros((n,n)) num = 1 for i in range((n-1)*(n-1)+1): for j in range(0,i+1): if j<=(n-1) and (i-j)<=(n-1): a[j][i-j] = num num += 1 else: continue 也在准备测开,感觉没准备好不敢轻易投递简历
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