题解 | 获得月份天数

#include <stdio.h>

short leapyear(int year)//判断是否为闰年。f=1是闰年。f=0,不是闰年
{
    short f = 0;
    if (year % 400 == 0)
        f = 1;
    if (year % 4 == 0 && year % 100 != 0)
        f = 1;
    return f;
}

int month_days(int year, int month)//返回year,month的天数
{
    int d[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
    if (leapyear(year)) d[2] = 29;
    return d[month];
}


int main(int argc, char const* argv[])
{
    int month = 0, year = 0;
    while ((scanf("%d%d", &year, &month)) == 2)
    {
        if (month > 12 || month < 1)
        {
            printf("月份输入有误，请重新输入\n"); continue;
        }
        printf("%d\n", month_days(year, month));
    }
}