题解 | 计算某字符出现次数

刚开始没有考虑数字的情况，总是输出的比预期多，加入数字区分之后如下

#include <iostream>
using namespace std;

int main() {
    string s;
    getline(cin,s);
    int length = s.length();
    char c;
    cin >> c;
    int count = 0;
    for(int i = 0;i<length;i++)
    {
        if(c == '0'||c == '1'||c== '2'||c == '3'||c == '4'||c == '5'||c == '6'||c == '7'||c == '8'||c == '9')
        {
            if(s[i] == c)
            {
                count++;
                continue;
            }
        }
        else  
        {
            if(s[i] == c || s[i]+32 == c ||  s[i]-32 == c)
            {
                count++;
                continue;
            }
        }
    }
    cout << count;
   
}
// 64 位输出请用 printf("%lld")