题解 | A + B
#include <bits/stdc++.h>
using namespace std;
string num[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
int stringToInt(string s) {
for (int i = 0; i < 10; i++) {
if (num[i] == s)return i;
}
return -1;
}
int realInt(string a) {
int x = 0;
while (a.find(' ') != a.size() - 1) {
x *= 10;
x += stringToInt(a.substr(0, a.find(' ')));
a = a.substr(a.find(' ') + 1);
}
x *= 10;
x += stringToInt(a.substr(0, a.find(' ')));
return x;
}
int main() {
string s;
while (getline(cin, s)) {
string a = s.substr(0, s.find('+'));
string b = s.substr(s.find('+') + 2);
b = b.substr(0, b.find('='));
int x = realInt(a), y = realInt(b);
if(x==0&&y==0)break;
cout<<x+y<<endl;
}
}
本题难度在于如何把int给抽出来,需要做大量实验去找index,然后得到的代码如上,整体难度很低
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