题解 | kiki算数

#include <stdio.h>
#include <string.h>

int main()
{
  unsigned int a, b;
  scanf("%d %d", &a, &b);
  char res[20];
  sprintf(res, "%u", a + b);// 将a+b的结果转换为字符串存储在res中
  int length = strlen(res);
  int sum = (res[length - 2]-'0') * 10 + (res[length - 1]-'0');
  printf("%d\n", sum);

  return 0;
}