题解 | 计算某字符出现次数

#include <stdio.h>
#include <string.h>

char str[1001] = { 0x00 };
char val = 0x00;
int count;

int main() {
    int len, b;

    // scanf("%s", str);
    gets(str);
    
    val = getchar();

    len = strlen(str);

    // printf("str is %s\r\nval is %c\r\n", str, val);

    for (int i = 0; i < len; i++)
    {
        if (val >= '0' && val <= '9') // 0 - 9
        {
            if (str[i] == val)
            {
                count++;
            }
        }else if (val >= 'a' && val <= 'z')  // a - z 
        {
            if (val == str[i] || str[i] == (val - 32))
            {
                count++;
            }
        }else if (val >= 'A' && val <= 'Z')  // A - Z
        {
            if (val == str[i] || str[i] == (val + 32))
            {
                count++;
            }
        }
    }

    printf("%d", count);

    return 0;
}