题解 | 输入n个整数，输出其中最小的k个

#2025，我想......# #刷题我是认真的#

解题重点：

1. 整理思路比较简单，先排序，再找前两个

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String[] str = in.nextLine().split(" ");
        String[] arr = in.nextLine().split(" ");
        int n = Integer.parseInt(str[0]);
        int k = Integer.parseInt(str[1]);
        int[] numArr = new int[n];
        for (int i = 0; i < n; i++) {
            numArr[i] = Integer.parseInt(arr[i]);
        }
        for (int i = 0; i < n; i++) {
            int tmp = numArr[i];
            int j = i - 1;
            while (j >= 0 && numArr[j] > tmp) {
                numArr[j + 1] = numArr[j];
                j--;
            }
            numArr[j + 1] = tmp;
        }
        for (int i = 0; i < k; i++) {
            System.out.print(numArr[i] + " " );
        }
    }
}