题解 | #游游的整数切割#
number = input()
def even_check(num):
even_list = ['2', '4','6', '8', '0']
if num[-1] in even_list:
return 0 # even
else:
return 1 # odd
count = 0
for i in range(1,len(number)):
part_a = number[:i]
part_b = number[i:]
a_result = even_check(part_a)
b_result = even_check(part_b)
if a_result == b_result:
count += 1
print(count)
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