题解 | 查询连续登陆的用户
select user_id
from (select user_id, start_date, count(start_date) cnt
from (select *, date_sub(log_date, interval rk day) start_date
from (select distinct user_id, date(log_time) log_date,
dense_rank() over(partition by user_id
order by date(log_time)) rk
from login_tb) t1) t2
group by user_id, start_date) t3
where user_id in (select user_id from register_tb)
group by user_id
having max(cnt)>=3
order by user_id asc;
查看15道真题和解析
腾讯公司福利 482人发布
投递谷歌等公司10个岗位 >