题解 | #压缩二维码#（Python3）
压缩二维码
https://www.nowcoder.com/practice/1150d36c2cd64df9bf373988486c6723
import sys
def func(n, arr):
# 矩阵转字符串
s = ''.join(arr)
ans = []
# 4个比特位算一个整数
for i in range(0, n*n, 4):
w = 0
# 计算整数值
for k in range(0, 4):
w = w * 2 + (1 if s[i+k]== '#' else 0)
ans.append(w)
return ans
# 输入读取
while True:
try:
n = int(input())
n = 1<<n
arr = [input() for i in range(0, n)]
result = func(n, arr)
for number in result:
print(number, end=' ')
print()
except EOFError:
break
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